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Maru [420]
3 years ago
12

What is the first step to solve this equation : 11-3x=44

Mathematics
2 answers:
Brrunno [24]3 years ago
6 0
11-3x= 44
Step 1: Subtract 11 from 11 = 0 and 44-11= 33
Step 2: Divide 3 by 3= 0 and divide 44 by 3 = 14.6
X= 14.6
Zolol [24]3 years ago
4 0

Answer:

Subtract 11 from both sides

Step-by-step explanation:

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Solve for y.<br> 8y-3y=40
Airida [17]

Answer:

8

Step-by-step explanation:

8y-3y=40

5y. = 40

y. =8

the value of y is 8.

...

5 0
3 years ago
Read 2 more answers
5. 40 = -1/3(9x + 30)+ 2
Natali5045456 [20]

Answer:

x = -16

Step-by-step explanation:

-1/3 * 9x = -3x

-1/3 * 30 = -10

-10 + 2 = -8

40 = -3x - 8

+8          +8

48 = -3x

---     ----

-3    -3

-16 = x

x = -16

~ Zoe

6 0
3 years ago
1) Calculate the distance between point A: (22,12) and point B: (30,27)​
DIA [1.3K]

Answer:

17

Step-by-step explanation:

√(x2 - x1)² + (y2 - y1)²

√(30 - 22)² + (27 - 12)²

√(8)² + (15)²

√ 64 + 225

√289

= 17

5 0
3 years ago
Solve x^2=64. What property did you use?
katovenus [111]

Answer:

x = ± 8 using the square root property

Square root both sides to get x = ± 8.

7 0
4 years ago
The distribution of the number of people in line at a grocery store has a mean of 3 and a variance of 9. A sample of the numbers
Airida [17]

Answer:

a) P(\bar X >4)=P(Z>\frac{4-3}{\frac{3}{\sqrt{50}}}=2.357)

P(Z>2.357)=1-P(Z

b) P(\bar X \frac{2.5-3}{\frac{3}{\sqrt{50}}}=-1.179)

P(Z

c)  

P(2.5 < \bar X< 3.5) = P(\frac{2.5-3}{\frac{3}{\sqrt{50}}}

P(-1.179Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Part a

Let X the random variable that represent the number of people of a population, and for this case we know that:

Where \mu=3 and \sigma=\sqrt{9}=3

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

From the central limit theorem we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And we want to find this probability:

P(\bar X >4)= P(z> \frac{4-3}{\frac{3}{\sqrt{50}}})

And using a calculator, excel or the normal standard table we have that:

P(Z>2.357)=1-P(Z

Part b

P(\bar X  \frac{2.5-3}{\frac{3}{\sqrt{50}}})

And using a calculator, excel or the normal standard table we have that:

P(Z

Part c

For this case we want this probability:

P(2.5 < \bar X< 3.5) = P(\frac{2.5-3}{\frac{3}{\sqrt{50}}}

And using a calculator, excel or the normal standard table we have that:

P(-1.179

7 0
3 years ago
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