Question

A spring-mass system is undergoing simple harmonic motion of amplitude 2.2 cm and angular frequency 10.4 s−1. The magnitude of the maximum acceleration of the mass as it oscillates back and forth is A spring-mass system is undergoing simple harmonic motion of amplitude 2.2 and angular frequency 10.4 . The magnitude of the maximum acceleration of the mass as it oscillates back and forth is a. 0.00 m/s2. b. 0.21 m/s2. c. 2.38 m/s2. d. 15.0 m/s2.

Answer 1

The maximum acceleration is c) $2.38 m/s^2$

Explanation:

The maximum acceleration of a spring-mass system is given by

$a_{max} = \omega^2 A$

where

$\omega$ is the angular frequency of the system

A is the amplitude of the motion

For the spring-mass system in this problem, we have

$A=2.2 cm = 0.022 m$ is the amplitude

$\omega=10.4 rad/s$ is the angular frequency

Substituting, we find the maximum acceleration:

$a_{max}=(0.022)(10.4)^2=2.38 m/s^2$

#LearnwithBrainly