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ICE Princess25 [194]
3 years ago
7

Newton’s law of universal gravitation stars that every object in the universe attracts every other object

Physics
1 answer:
LenaWriter [7]3 years ago
4 0

Yes it does !  Uh huh. Right you are. Truer words are seldom written.

You have quoted the law quite accurately but also incompletely.  

Do you have a question to ask ?

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How do magnetic stripes show the history of earth's magnetic field?
Mama L [17]
If i could heat a piece of iron so that it melted, and then held a magnet close to the molten iron and then let the iron cool to room temperature, you could use a microscope to look at the iron and tell that a magnet had been present during cooling. you could even tell if it was the north or south pole of the magnet that i held close to the molten iron.

Magma/lava contains a lot of molten iron so that when it erupts from a volcano and cools, the magnetic field of the earth leaves an imprint in it, just like the cooling iron from above. From this imprint we can tell the strength of the magnetic field and also which direction the north and south poles were at the time.
3 0
3 years ago
Determine the amount of thermal energy that must be transferred to a copper wire (mass 20g) to
Colt1911 [192]

Answer:  Thermal energy is 8,2 kJ

Explanation:  Heat Q = m c ΔT .    c = 385 J/kg C  and

ΔT = (1085 - 25)C = 1060 C.   Q = 0.020 kg · 385 J / (kg C) ·1060 C

= 8162 J

8 0
3 years ago
the resistivity of gold is 2.44×10−8Ω⋅m at room temperature. A gold wire that is 0.9 mm in diameter and 14 cm long carries a cur
cricket20 [7]

Answer:

0.03605 V/m is the electric field in the gold wire.

Explanation:

Resistivity of the gold = \rho = 2.44\times 10^{-8} \Omega.m

Length of the gold wire = L = 14 cm = 0.14 m ( 1 cm = 0.01 m)

Diameter of the wire = d = 0.9 mm

Radius of the wire = r = 0.5 d = 0.5 × 0.9 mm = 0.45 mm = 0.45\times 0.001 m

( 1mm = 0.001 m)

Area of the cross-section = A=\pi r^2=\pi r^(0.45\times 0.001 m)^2

Resistance of the wire = R

Current in the gold wire = 940 mA = 0.940 A ( 1 mA = 0.001 A)

R=\rho\times \frac{L}{A}

V(voltage)=I(current)\times R(Resistance) ( Ohm's law)

\frac{V}{I}=\rho\times \frac{L}{A}

We know, Electric field is given by :

E=\frac{dV}{dr}

E=\frac{V}{L}

E=\frac{V}{L}=\rho\times \frac{I}{A}

E=2.44\times 10^{-8} \Omega.m\times \frac{0.940 A}{\pi r^(0.45\times 0.001 m)^2}=0.03605 V/m

0.03605 V/m is the electric field in the gold wire.

3 0
3 years ago
CAN ANYONE HELP PLEASE I NEED THIS DONE BY TODAY!! I WILL MARK YOU BRIANLYIST.
bulgar [2K]
I have no idea my dude sorry
7 0
3 years ago
Jacques is trying to put a screw into a hard piece of wood, but it is too difficult for him to turn. Which of the following woul
solniwko [45]

Answer:

A. It is the only one that makes sense

Explanation:

3 0
4 years ago
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