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Brilliant_brown [7]
3 years ago
9

Which tool would be most useful to identify areas with frequent earthquakes to predict future earthquakes?

Physics
1 answer:
enyata [817]3 years ago
6 0
It is a seismograph that would be most useful.
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A person weighs 60 kg. The area under the foot of the person is 150 cm2. Find the pressure exerted on the ground by the person.
9966 [12]

Answer:

40000 N/m²

Explanation:

Applying,

P =  F/A................... Equation 1

Where P = Pressure, F = Force, A = Area.

From the question,

The force(F) exerted by the person's foot is thesame as it's weight.

F = W = mg............ Equation 2

Where m = mass of the person, g = acceleration due to gravity.

Substitute equation 2 into equation 1

P = mg/A................ Equation 3

Given: m = 60 kg, g = 10 m/s², A = 150 cm² = (150/10000) m² = 0.015 m²

Substitute these values into equation 3

P = (60×10)/0.015

P = 600/0.015

P = 40000 N/m²

3 0
3 years ago
When a beam of charged particles moves through a magnetic field, what is the evidence that particles in the beam have momentum g
Vsevolod [243]

The charged particles are often deflated in a magnetic field.

<h3>What is a magnetic field?</h3>

The term charge refers to a positive or negative entity. The can be created when a charge is made to pass through a conductor in a magnetic field.

A magnetic field is created when we have a north pole and a south pole. The charged particles could be made to pass through the electric field and when that happens, we can see a pattern a shown in the image attached.

Thus, we can see that the charged particles are often deflated in a magnetic field.

Learn more about magnetic field:brainly.com/question/23096032

#SPJ1

4 0
1 year ago
Which of the following are events?
ira [324]

Answer:

G..................

3 0
3 years ago
A circular radar antenna on a coast guard ship has a diameter of 2.10 m and radiates at a frequency of 16.0 ghz. two small boats
solmaris [256]
By definition,
q = 1.22y/D

Where,
q = min. angle
y = wavelength
D = Aperture diameter = diameter of the antenna

At distance "x" from the antenna,
L =xq = 1.22xy/D
Where, L = Min. distance

But, y =c/f = (3*10^8)/(16*10^9) = 0.01875 m

Substituting;
L = 1.22*5*10^3*0.01875/2.1 = 54.46 m
5 0
4 years ago
Please help me out as soon as you can. Really need help.
olga nikolaevna [1]
The answer would be 6 because 2.0x3= 6

(newton’s 2nd law)

mark me brainliest
4 0
3 years ago
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