∫(t = 2 to 3) t^3 dt
= (1/4)t^4 {for t = 2 to 3}
= 65/4.
----
∫(t = 2 to 3) t √(t - 2) dt
= ∫(u = 0 to 1) (u + 2) √u du, letting u = t - 2
= ∫(u = 0 to 1) (u^(3/2) + 2u^(1/2)) du
= [(2/5) u^(5/2) + (4/3) u^(3/2)] {for u = 0 to 1}
= 26/15.
----
For the k-entry, use integration by parts with
u = t, dv = sin(πt) dt
du = 1 dt, v = (-1/π) cos(πt).
So, ∫(t = 2 to 3) t sin(πt) dt
= (-1/π) t cos(πt) {for t = 2 to 3} - ∫(t = 2 to 3) (-1/π) cos(πt) dt
= (-1/π) (3 * -1 - 2 * 1) + [(1/π^2) sin(πt) {for t = 2 to 3}]
= 5/π + 0
= 5/π.
Therefore,
∫(t = 2 to 3) <t^3, t√(t - 2), t sin(πt)> dt = <65/4, 26/15, 5/π>.
can you give more detail?
Answer:
option A, option C, option D
Step-by-step explanation:
a) 1 ÷ m/6
can be written as
÷ 
b) sides in (m/6) will change if both has to multiply
c) 1 ÷ m/6
can be written as
1 * 6/m
1(
) and wont make change to answer. so matches with the question.
d)
1 ÷ m/6
1 * 6/m
1 * 6 * 
6 *
6 ÷ m ..therefore true
e)
1 ÷ m/6
1 * 6/m
6/m ....does not match or can be converted to the following so wrong
- Therefore A, C, D are correct and B and E is wrong.
Perimeter of 1 tablecloth = 3+3+2+2= 10
Total fringe needed = 10x3 = 30 meters
Answer:
6x
Step-by-step explanation:
