3 years ago

What is 25 more than 50 as an expression

Mathematics

2 answers:

Aleks [24]3 years ago

6 0

Answer: 75

Step-by-step explanation: 25+50

lesya [120]3 years ago

3 0

Answer:75

Step-by-step explanation: 50 + 25

You might be interested in

What is the area of a quadrilateral with vertices at (-2,0), (3,0), (3/4), and (-2,4)?

Serggg [28]

Answer: 20

Step-by-step explanation:

7 0

2 years ago

LOOK AT PIC PLSS TYYYYY

slava [35]

Answer:

2.52 lbs=40.32 oz

Step-by-step explanation:

I used the mass formula and I even searched it.

2.52 lbs=40.32 oz

Hope this helps! :)

7 0

2 years ago

Find all of the zeros of f(x) = 5x^2 +40x-100

Umnica [9.8K]

Answer:the answer is B

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Evaluate C_n.xP^xQn-x For the given n=7, x=2, p=1/2

r-ruslan [8.4K]

Answer:

The value of given expression is $\frac{21}{128}$ .

Step-by-step explanation:

Given information: n=7, x=2, p=1/2

$q=1-p=1-\frac{1}{2}=\frac{1}{2}$

The given expression is

$C(n,x)p^xq^{n-x}$

It can be written as

$^nC_xp^xq^{n-x}$

Substitute n=7, x=2, p=1/2 and q=1/2 in the above formula.

$^7C_2(\frac{1}{2})^2(\frac{1}{2})^{7-2}$

$\frac{7!}{2!(7-2)!}(\frac{1}{2})^2(\frac{1}{2})^{5}$

$\frac{7!}{2!5!}(\frac{1}{2})^{2+5}$

$\frac{7\times 6\times 5!}{2\times 5!}(\frac{1}{2})^{2+5}$

$21(\frac{1}{2})^{7}$

$\frac{21}{128}$

Therefore the value of given expression is $\frac{21}{128}$ .

7 0

3 years ago

Which values of a and b make the following equation true?

zzz [600]

Answer:

A. is correct answer

Step-by-step explanation:

full explanation

6 0

2 years ago