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SVETLANKA909090 [29]
3 years ago
11

would you rather read 12 pages every night in a chapter book with 144 pages or read 50 pages 3 times a week in a chapter book wi

th 1322 pages
Mathematics
2 answers:
podryga [215]3 years ago
5 0

Answer:

the 1st one because it would take 12 days to finish

Step-by-step explanation:

the second one would take about 8 weeks

xenn [34]3 years ago
4 0

Answer:

It depends on if you like reading or not

Step-by-step explanation:

the first option would be much better for people that don't like reading because you would get the book done in 12 days while only reading 12 pages a night. In the other option it would take more than 3 weeks and you'd have to read much more

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If a roll of painter's tape contains 14 feet of tape, what is the maximum number of 1.75-foot pieces that can be cut from the ro
Dafna11 [192]
Answer is c 8
8*1.75=14
3 0
2 years ago
PLEASE ANSWER the most understandable will get brainliest
katrin2010 [14]

Answer:

I think it should be the 1st one

Step-by-step explanation:

sorry if it is wrong hope it helps

4 0
3 years ago
Write an addition equation that can help you find 9 - 6. Explain your answer
vfiekz [6]
9 - 6 = 3
so 3 + 6 = 9  which is an addition equation that helps you find the answer. 

6 0
3 years ago
Read 2 more answers
If the radius of the circle is multiplied by a factor of 3, then the area of the circle is multiplied by a factor of
Oksi-84 [34.3K]
\bf \textit{area of a circle}\\\\
A=\pi r^2\quad 
\begin{cases}
r=radius\\
-----\\
r=\stackrel{r\times 3}{3r}
\end{cases}\implies A=\pi (3r)^2
\\\\\\
A=\pi (3^2r^2)\implies A=9(\pi r^2)

notice, if the original area was πr², then the new area has a factor in front of it, that much.
8 0
3 years ago
Cos (90-theta) • cosec90-theta) =tano. How?​
denis-greek [22]

Answer:

<u>______________________________________________________</u>

<u>TRIGONOMETRY IDENTITIES TO BE USED IN THE QUESTION :-</u>

For any right angled triangle with one angle α ,

  • \cos (90 - \alpha  ) = \sin \alpha  or  \sin(90 - \alpha ) = \cos\alpha
  • cosec \: (90 - \alpha  ) = \sec\alpha   or  \sec(90 - \alpha ) = cosec\:\alpha

<u>SOME GENERAL TRIGNOMETRIC FORMULAS :-</u>

  • <u></u>\sin \alpha = \frac{1}{cosec \: \alpha }  or  cosec \: \alpha  = \frac{1}{\sin \alpha }
  • <u></u>\cos \alpha = \frac{1}{\sec \alpha }  or  \sec \alpha = \frac{1}{\cos \alpha }

<u>______________________________________________________</u>

Now , lets come to the question.

In a right angled triangle , let one angle be α (in place of theta) .

So , lets solve L.H.S.

\cos (90 - \alpha ) \times cosec(90 - \alpha )

=> sin\alpha  \times \sec\alpha

=> \sin\alpha  \times \frac{1}{\cos\alpha }

=> \frac{\sin\alpha }{\cos\alpha }

=> \tan\alpha = R.H.S.

∴ L.H.S. = R.H.S. (Proved)

3 0
3 years ago
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