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3 years ago

How many valence electrons does fluorine have?

Chemistry

2 answers:

aalyn [17]3 years ago

4 0

Answer:

Fluorine (F) has 7 valence electrons.

Explanation:

Fluorine (F) has 7 valence electrons. Fluorine belongs to group 7 in the periodic table. Group 7 elements are known as halogens. Fluorine is halogen and is the most electronegative element among the halogens. As Fluorine (F) has 7 valence electrons it has a tendency to accept another electron and complete an octet (8 electrons). Fluorine (F) forms a fluoride ion (anion) by accepting one more electron in its valence shell.

ahrayia [7]3 years ago

3 0

Seven valence electrons .

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Which is true of cell differentiation?

SSSSS [86.1K]

Answer:

Explanation:

When stem cells differentiate, they are different (almost like mutation).

8 0

3 years ago

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What is the mass for 3.01*10 23 molecules h2o

Genrish500 [490]

M H₂O: 1g×2 + 16g = 18g


6,02×10²³ --------- 18g
3,01×10²³ --------- Xg
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X = 9g

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7 0

4 years ago

Read 2 more answers

Iron (III) oxide and hydrogen react to form iron and water, like this: Fe 03(s)+3H9)2Fe(s)+3HO) At a certain temperature, a chem

belka [17]

The question is incomplete, here is the complete question:

Iron (III) oxide and hydrogen react to form iron and water, like this:

$Fe_2O_3(s)+3H_2(g)\rightarrow 2Fe(s)+3H_2O(g)$

At a certain temperature, a chemist finds that a 8.9 L reaction vessel containing a mixture of iron(III) oxide, hydrogen, Iron, and water at equilibrium has the following composition.

Compound Amount

Fe₂O₃ 3.95 g

H₂ 4.77 g

Fe 4.38 g

H₂O 2.00 g

Calculate the value of the equilibrium constant Kc for this reaction. Round your answer to 2 significant digits.

Answer: The value of equilibrium constant for given equation is $1.0\times 10^{-4}$

Explanation:

To calculate the molarity of solution, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}}{\text{Molar mass of solute}\times \text{Volume of solution (in L)}}$

For hydrogen gas:

Given mass of hydrogen gas = 4.77 g

Molar mass of hydrogen gas = 2 g/mol

Volume of the solution = 8.9 L

Putting values in above expression, we get:

$\text{Molarity of hydrogen gas}=\frac{4.77}{2\times 8.9}\\\\\text{Molarity of hydrogen gas}=0.268M$

For water:

Given mass of water = 2.00 g

Molar mass of water = 18 g/mol

Volume of the solution = 8.9 L

Putting values in above expression, we get:

$\text{Molarity of water}=\frac{2.00}{18\times 8.9}\\\\\text{Molarity of water}=0.0125M$

For the given chemical equation:

$Fe_2O_3(s)+3H_2(g)\rightarrow 2Fe(s)+3H_2O(g)$

The expression of equilibrium constant for above equation follows:

$K_{eq}=\frac{[H_2O]^3}{[H_2]^3}$

Concentration of pure solids and pure liquids are taken as 1 in equilibrium constant expression.

Putting values in above expression, we get:

$K_{c}=\frac{(0.0125)^3}{(0.268)^3}\\\\K_{c}=1.0\times 10^{-4}$

Hence, the value of equilibrium constant for given equation is $1.0\times 10^{-4}$

6 0

4 years ago

Using the periodic table to locate each element, write the electron configuration of(c) Re.

Aleksandr [31]

Rhenium is a chemical element with the symbol Re and atomic number 75. The electron configuration of Re is [Xe] $6s^{2} 4f^{14} 5d^{5}$ .

<h3>How to write an electronic configuration?</h3>

1. Identify the given element and its atomic number from the periodic table.

2. Write the electron configuration by the energy level and the type of orbital first, then the number of electrons present in the orbital as superscript.

The easiest way to write the electronic configuration for any element is by using a diagonal rule for electron filling order in the different subshells according to the Aufbau principle.

The 3 rules for writing the electron configuration in the orbital box diagram are – the Aufbau rule, the Pauli-exclusion rule, and Hund's Rule.

To learn more about electronic configuration, refer

https://brainly.ph/question/73419

#SPJ4

5 0

2 years ago

A sample of gas occupies a volume of 67.1 mL . As it expands, it does 135.3 J of work on its surroundings at a constant pressure

Semmy [17]

Answer:

$V_2=1.363x10^{-3}m^3=1363mL$