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vladimir1956 [14]
3 years ago
13

Find the probability that when a couple has sixsix ​children, at least one of them is a girlgirl. ​(assume that boys and girls a

re equally​ likely.)
Mathematics
1 answer:
Vaselesa [24]3 years ago
6 0

Answer: \frac{63}{64}

<u>Step-by-step explanation:</u>

"At least one" means:

(1g & 5b) or (2g & 4b) or (3g & 3b) or (4g & 2b) or (5g & 1b) or (6g & 0b)

which is the same as: not(0g & 6b)

<u>not (0g & 6b)</u>

= 1 - [(\frac{1}{2})^{0}*(\frac{1}{2})^{6} ]

= 1 - 1 * \frac{1}{64}

= 1 - \frac{1}{64}

= \frac{63}{64}

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