Question

Consider the equations y = |x − 1| and y = 3x + 2.

Answer 1

Answer:

The approximate solution of  y = |x − 1| and y = 3x + 2 is (-0.2,1.2) .

Step-by-step explanation:

As given the equations

y = |x − 1| and y = 3x + 2

Thus two equation becomes

x - 1 = 3x + 2

- (x-1) = 3x + 2

Take

- (x-1) = 3x + 2

-x + 1 = 3x + 2

-3x - x = 2 -1

-4x = 1

$x = \frac{-1}{4}$

x = -0.2 (Approx)

Putting in the equation y = |x − 1|

y = |-0.2 − 1|

y = |-1.2|

y = 1.2

Therefore the approximate solution of  y = |x − 1| and y = 3x + 2 is (-0.2,1.2) .

Answer 2

(-0.2,1.2)

substitute 3x+2 for y and set them equal to eachother then plug in x for y