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4 years ago

Are these triangles similar?

Mathematics

2 answers:

EleoNora [17]4 years ago

8 0

Answer:

yes

Step-by-step explanation:

If two pairs of corresponding angles in a pair of triangles are congruent, then the triangles are similar. We know this because if two angle pairs are the same, then the third pair must also be equal. When the three angle pairs are all equal, the three pairs of sides must also be in proportion

Sav [38]4 years ago

8 0

No There not similar

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Calculate the sample variance and sample standard deviation for the following frequency distribution of heights in centimeters f

Zolol [24]

Answer:

$\bar X = \frac{\sum_{i=1}^n X_i f_i}{n}= \frac{22026.1}{171}=128.81$

$s^2 = \frac{2839948.85- \frac{(22026.1)^2}{171}}{171-1}= 16.59$

$s= \sqrt{16.587}=4.07$

Step-by-step explanation:

For this case we can calculate the sample variance and deviation with the following table

Class Midpoint (Xi) fi Xi*fi Xi^2 *fi

120.6-123.6 122.1 17 2075.7 253443

123.7-126.7 125.2 49 6134.8 768077

126.8-129.8 128.3 29 3720.7 477365.8

129.9-132.9 131.4 41 5387.4 707904.4

133.0-136.0 134.5 35 4007.5 633158.8

___________________________________________

Total 171 22026.1 2839948.85

For this case we can calculate the mean or expected value with the following formula:

$\bar X = \frac{\sum_{i=1}^n X_i f_i}{n}= \frac{22026.1}{171}=128.81$

Now we can calculate the sample variance with the following formula:

$s^2 =\frac{\sum f_i X^2_i -[\frac{(\sum X_i f_i)}{n}]^2}{n-1}$

And if we replace we got:

$s^2 = \frac{2839948.85- \frac{(22026.1)^2}{171}}{171-1}= 16.59$

And the standard deviation would be the square root of the variance and we got:

$s= \sqrt{16.59}=4.07$

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