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Lapatulllka [165]
2 years ago
12

Find the length of the hypotenuse round your answer to the nearest hundred

Mathematics
1 answer:
Ede4ka [16]2 years ago
5 0
A. 7+4=11. That’s the answer to the hypotenuse.
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Simplify the expression. 5g – 7g + 4 + 2g
Marina86 [1]

Answer:

4

Step-by-step explanation:

there is no quantity for g and 4 is all that is left

4 0
3 years ago
TW¯¯¯¯¯¯¯¯¯=14.6, CW¯¯¯¯¯¯¯¯¯=6, TU¯¯¯¯¯¯¯=21.2. Find the value of VW¯¯¯¯¯¯¯¯¯.
pogonyaev

TW x WU = CW x VW

Fill in the known values:

WU = TU - TW = 21.2 - 14.6 = 6.6

14.6 x 6.6 = 6 x VW

Simplify:

96.36 = 6VW

Divide both sides by 6:

VW = 96.36 / 6

VW = 16.06

Round to one decimal place:

VW = 16.1

The answer is D>

8 0
3 years ago
Read 2 more answers
Help with length of hypotenuse ​
Salsk061 [2.6K]

Answer:

sqrt(10) *x

Step-by-step explanation:

Since this is a right triangle, we can use the Pythagorean theorem

a^2 + b^2 = c^2

x^2 + (3x)^2 = hypotenuse ^2

x^2 + 9x^2 = hypotenuse ^2

10x^2 = hypotenuse  ^2

Take the square root of each side

sqrt( 10x^2) =  sqrt(hypotenuse  ^2)

sqrt(10) * x = hypotenuse

5 0
3 years ago
Read 2 more answers
Jake can cut and split a cord of firewood in 9 fewer hours than Dwight can. When they work together, it takes them 6 hours. How
Luba_88 [7]

Answer:

18 hours for Dwight, 9 hours for Jake

Step-by-step explanation:

If J is the time it takes for Jake working alone, and D is the time it takes for Dwight working alone, then:

J = D − 9

Working together, Jake's speed plus Dwight's speed equals 1 cord per 6 hours.

1 / J + 1 / D = 1 / 6

Solve the system of equations by substituting for J:

1 / (D − 9) + 1 / D = 1 / 6

Multiply both sides by D − 9.

1 + (D − 9) / D = (D − 9) / 6

Multiply both sides by D:

D + D − 9 = D (D − 9) / 6

Simplify and solve:

2D − 9 = (D² − 9D) / 6

12D − 54 = D² − 9D

0 = D² − 21D + 54

0 = (D − 3) (D − 18)

D = 3 or 18

Since J = D − 9, D must be greater than 9.  So D = 18 and J = 9.

That means it takes Dwight 18 hours working alone, and it takes Jake 9 hours working alone.

3 0
3 years ago
The product of two consecutive whole numbers is less than the sum of the square of the smaller number and 13
Norma-Jean [14]

Answer: a<13

Step-by-step explanation:

a*(a+1)<a^2+13

a^2+a<a^2+13

subtract a^2 from both sides:

a<13

8 0
3 years ago
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