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Reil [10]
3 years ago
14

A balloon of helium gas in Alabama has a volume of 22.4 L at 26°C and a 1.03 ATM how big with a balloon get if is transported to

Denver on a sunny day when it is 22°C and has an air pressure of 0.81 ATM
Chemistry
1 answer:
Dimas [21]3 years ago
8 0

Answer:

The final volume of the balloon is = 28.11 L

Explanation:

Initial pressure P_{1} = 1.03 atm = 104.325 K pa

Initial temperature T_{1} = 26 °c = 299 K

Initial volume V_{1} = 22.4 L

Final temperature T_{2} = 22 °c = 295 K  

Final pressure P_{2} = 0.81 atm = 82 K pa

We know that

\frac{P_{1} V_{1} }{T_{1} } = \frac{P_{2} V_{2} }{T_{2} }

Put all the values in above formula we get

\frac{(104.325)(22.4)}{299} = \frac{(82)(V_{2} )}{295}

V_{2} = 28.11 L

This is the final volume of the balloon.

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POINTS!!!
lisabon 2012 [21]
The answer is selenium which is D
8 0
3 years ago
Change 32L of carbon dioxide into moles of carbon dioxide
kaheart [24]
32L —> 32000g —> 727.116 Moles (rounded)
7 0
3 years ago
1. When you have 43 grams of sodium, how many grams of NaCl can you produce?
seropon [69]

Molar mass is the amount grams that one mole weighs.

Explanation: You need to find the molar mass of NaCl which is the same as the amu on the periodic table in grams. So it is 22.99(Na) + 35.45(Cl) = 58.44

You also know that for every mole of NaCl you have 1 mole of Na because every molecule of NaCl has 1 atom of Na.

Finally, using the periodic table, again, you see that the molar mass of Na is 22.99.

Then using stoichiometry, you can find the grams of sodium.

100(g NaCl) * 1 mol (NaCl)/58.44 g (NaCl) * 1 mol (Na)/ 1 mol (NaCl) * 22.99 (g of Na)/ 1 mol (Na)

which equals 39.339435 g of Na.

If you need to maintain significant figures the answer will be 40.

hope this helps

6 0
3 years ago
The balanced combustion reaction for C 6 H 6 is 2 C 6 H 6 ( l ) + 15 O 2 ( g ) ⟶ 12 CO 2 ( g ) + 6 H 2 O ( l ) + 6542 kJ If 8.10
Nataly [62]

Answer:

The final temperature of water = 35.2 °C

Explanation:

Step 1: Data given

Mass of C6H6 = 8.100 grams

Mass of water = 5691 grams

Temperature = 21 °C

Step 2: The balanced equation

2C6H6(l) + 15O2(g) ⟶ 12 CO2 (g) + 6H2O (l) + 6542 kJ

Step 3:

Q = m*c*ΔT.

⇒with Q = the heat released during this reaction (this depends on the amount of reactants used)

⇒ with m=  the mass of the water

⇒with c = the "specific heat" of water = how much energy it takes to raise the temp of 1g of water by 1°C

⇒with ΔT = the change in the temperature of the water

 

For every 2 moles of C6H6 consumed, 6542 kJ of heat is released.  

Step 4: Calculate moles for 8.100 grams

8.100grams / 78.11 g/mol= 0.1037 mol es

So, according to the equation, the amount of heat released is:

(0.1037 moles / 2 moles)* (6542 kJ) = 339.2 kJ

Step 5: Calculate the final temperature

Q = mcΔT

ΔT = Q / (m*c)

T2- T1 = Q / (m*c)

T2 = [Q / (m*c)] + T1 = [(339.2 kJ) / (5691g)(0.004186 kJ/g°C)] + 21°C = 35.2°C

The final temperature of water = 35.2 °C

8 0
3 years ago
Several teeth were found in an area of flat land covered with trees and plants. The teeth were examined by a paleontologist, and
djverab [1.8K]
B because that makes the most sense
3 0
3 years ago
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