The volume (in liters) that the gas will occupy if the pressure is increased to 13.5 atm and the temperature is decreased to 15 °C is 15 L
From the question given above, the following data were obtained:
Initial pressure (P₁) = 8.5 atm
Initial volume (V₁) = 24 L
Initial temperature (T₁) = 25 °C = 25 + 273 = 298 K
Final pressure (P₂) = 13.5 atm
Final temperature (T₂) = 15 °C = 15 + 273 = 288 K
<h3>Final volume (V₂) =? </h3>
- The final volume of the gas can be obtained by using the combined gas equation as illustrated below:

Cross multiply
298 × 13.5 × V₂ = 204 × 288
4023 × V₂ = 58752
Divide both side by 4023

<h3>V₂ = 15 L </h3>
Therefore, the final volume of the gas is 15 L
Learn more: brainly.com/question/25547148
Kinetic energy due to the movement
Answer: 37.6 atm
Explanation:
Given that,
Initial volume of gas (V1) = 19L
Initial pressure of gas (P1) = 9.5 atm
Final volume of gas (V2) = 4.8L
Final pressure of gas (P2) = ?
Since pressure and volume are given while temperature remains the same, apply the formula for Boyle's law
P1V1 = P2V2
9.5 atm x 19L = P2 x 4.8L
180.5 atm•L = 4.8L•P2
Divide both sides by 4.8L
180.5 atm•L/4.8L = 4.8L•P2/4.8L
37.6 atm = P2
Thus, the final pressure is 37.6 atmospheres.