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ella [17]
3 years ago
7

2. A block of material has a volume of 2 m3. It has a mass of 1 × 104 kg. Calculate the density of the material sample and expre

ss your results in g/cm3 with appropriate scientific notation.
Chemistry
1 answer:
maks197457 [2]3 years ago
7 0
Density = mass / volume

D = 1 x 10⁴ / 2

D = 5000 kg/m³ in g/cm³:

1 kg/m³ ---------------- 0.001 g/cm³
5000 kg/m³ ----------- ??

5000 x 0.001 / 1 =>  5.0 g/cm³

hope this helps!
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2.
katovenus [111]

Answer:

A. 6atm

Explanation:

Using pressure law equation:

P1/T1 = P2/T2

Where;

P1 = initial pressure (atm)

T1 = initial temperature (K)

P2 = final pressure (atm)

T2 = final temperature (K)

According to this question;

P1 = 3 atm

P2 = ?

T1 = 120K

T2 = 240K

Using P1/T1 = P2/T2

3/120 = P2/240

Cross multiply

240 × 3 = P2 × 120

720 = 120P2

P2 = 720/120

P2 = 6atm

4 0
2 years ago
Name two metals alloyed with iron to make stainless steel.
kirill115 [55]
For stainless steel different kinds of compositions are used. Based on that different series of stainless steel has been coined.
1. Series 200 - Iron alloyed with <span>chromium, nickel and manganese.
2. Series 300 - It has 
a. Stainless Steel 304 - it has composition of 18% chromium and 8% Nickel
b. </span>Stainless Steel 316 - This has 18% chromium and 10% Nickel

Each kind of stainless steel is of different cost and has different applications.
7 0
2 years ago
How many milliliters of 4.00 M NaOH are required to exactly neutralize 50.0 milliliters of a 2.00 M solution of HNO3 ?
kramer

Answer: The volume of NaOH required is 25.0 ml

Explanation:

According to the neutralization law,

n_1M_1V_1=n_2M_2V_2

where,

n_1 = basicity HNO_3 = 1

M_1 = molarity of HNO_3 solution = 2.00 M

V_1 = volume of  HNO_3 solution = 50.0 ml

n_2 = acidity of NaOH = 1

M_1 = molarity of NaOH solution = 4.00 M

V_1 = volume of  NaOH solution =  ?

Putting in the values we get:

1\times 2.00\times 50.0=1\times 4.00\times V_2

V_2=25.0ml

Therefore, volume of NaOH required is 25.0 ml

3 0
2 years ago
When a 10 mL graduated cylinder is filled to the 10 mL mark, the mass of the water was measured to be 10.085 g at 20ºC. If the d
Arte-miy333 [17]
The percentage error is the error of the measured value to the true value. To find he percent error, the equation is as follows:

Percent error = |Measured Value - True Value|/True Value  * 100
The || is needed to get the absolute value of the difference. Substituting the values,

Percent error = |(10.085 g/10 mL) - 0.9975 g/mL|/<span>0.9975 g/mL  * 100
</span><em>Percent error = 1.1% </em>
8 0
3 years ago
An atom bonds with another atom. What is the best classification for this reaction?
defon
Chemical would be the correct answer
5 0
3 years ago
Read 2 more answers
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