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nevsk [136]
3 years ago
15

Which change occurs at the anode in an operating electrochemical cell?

Chemistry
1 answer:
murzikaleks [220]3 years ago
6 0

Answer:loss of electrons

Explanation:

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.A gas occupies 25,3 mL at a pressure of 152 kPa. Find the volume if the pressure is
Strike441 [17]

Answer:

47.36mL

Explanation:

Using Boyles law equation, which states that:

P1V1 = P2V2

Where;

V1 = initial volume (mL)

V2 = final volume (mL)

P1 = initial pressure (atm)

P2 = final pressure (atm)

Based on the provided information, V1 = 25.3mL, P1 = 152 kPa, V2 = ?, P2 = 0.804atm

First, we need to convert 152kPa to atm by dividing by 101

1kPa = 0.0099atm

152kPa = 1.505atm

P1V1 = P2V2

1.505 × 25.3 = 0.804 × V2

38.08 = 0.804V2

V2 = 38.08/0.804

V2 = 47.36mL

5 0
3 years ago
For any point on earths surface its height above sea level is called its
DedPeter [7]
Altitude, If this helped please 5 star me 
6 0
3 years ago
Read 2 more answers
Write a balanced chemical equation for the neutralization reaction between phosphoric acid and rubidium hydroxide.
Anastaziya [24]
Phosphoric acid is a weak acid, while rubidium hydroxide is a strong acid.

H₃PO₄ + RbOH --> Rb₃PO₄ + H₂O

We get Rb₃PO₄ because PO₄ has a charge of 3-, that is PO₄³⁻. Rb has a charge of 1+. You give the subscript of one the charge of the other as this is an ionic compound. So you end up with Rb₃PO₄, a neutral compound.

Now let's balance the equation:
H₃PO₄ + 3RbOH --> Rb₃PO₄ + 3H₂O
5 0
3 years ago
Plz help me it a timed test
Shtirlitz [24]

Answer:

B

Explanation:

6 0
3 years ago
Calculate the concentration of hydrogen ions in a healthy person’s blood that has a pH of 6.40.
adoni [48]

Answer:

[H⁺] = 3.98×10⁻⁷ M

Explanation:

Given data:

pH of blood = 6.40

Hydrogen ion concentration = ?

Solution:

Formula:

pH = - log[H⁺]

by rearranging this formula,

[H⁺] =  10⁻(pH)

By putting values,

[H⁺] = 10 ⁻⁶°⁴⁰

[H⁺] = 3.98×10⁻⁷ M

4 0
3 years ago
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