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Tema [17]
4 years ago
10

Cell Walls Function (short)

Chemistry
1 answer:
bazaltina [42]4 years ago
6 0
The main functions of the cell wall are to provide structure, support, and protection for the cell.
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A family ppoo holds 10000 gallons of water. how many cubic meters is this
yKpoI14uk [10]

10000 gallons= 37.85 cubic feet

7 0
3 years ago
How many miles can a commercial jetliner flying at 253 meters per second travel in 6.0 hours
Goryan [66]
1 mile = 1609.344 meters
1 hour = 3600 seconds 345.48 miles per hour x 1609.344
meters/mile x 1hour/3600seconds = 154.44 meter per second~~ANSWERR
6 0
4 years ago
What are Intensive and Extensive properties?
lianna [129]
Intensive properties are the properties which values doesnt change with the amount of mass or material that you have, example density, melting point boiling point, molecular mass

Extensive are properties that depends of how much mass or material you have. Example: mass, number of moles, volume, pressure, number of students, population, 

mass, volume, quantity (there is only one of each), color, reflect light, temperature, energy
5 0
3 years ago
Determine the frequency of radiation whose wavelength is 7.67 x 10^-7 cm. Then, determine the amount of energy in the radiation.
dimulka [17.4K]

Answer:

They frequency = 3.9 * 10^16 Hz

The amount of energy E = 2.58 *10^-17 J

Explanation:

Step 1: Data given

wavelength is 7.67 * 10^-7 cm

Step 2: Calculate the frequency

f = c / λ

⇒ with  λ = the wavelength in nm = 7.67 nm

⇒ with c = the speed of light  = 3.00 * 10^8 m/s

⇒ f = the frequency = TO BE DETERMINED

f = (3.00 * 10^8 m/s) / 7.67 * 10^-9 m

f = 3.9 * 10 ^16 /s = 3.9 * 10^16 Hz

They frequency is 3.9 * 10^16 Hz

Step 3: Calculate the amount of energy

E  =  h *f

⇒ with E = the amount of energy (in joule)

⇒ h = Planck's constant =  6.626  *10^-34 J*s

⇒ with f = the frequency

E =  6.626  *10^-34 J*s * 3.9 * 10^16 Hz

E = 2.58 *10^-17 J

8 0
3 years ago
Nuclear decay occurs according to first-order kinetics. What is the half-life of europium-152 if a sample decays from 10.0 g to
djyliett [7]

Answer:

13.5 years

Explanation:

Initial Concentration [Ao] = 10g

Final Concentration [A] = 0.768g

Time t= 50 years

Half life t1/2 = ?

These quantities are related by the following equations;

ln[A] = ln[Ao] - kt ......(i)

t1/2 = ln(2) / k ...........(ii)

where k = rate constant

Inserting the values in eqn (i) and solving for k, we have;

ln(0.768) = ln(10) - k (50)

-0.2640 = 2.3026 - 50k

50k = 2.3026 + 0.2640

k = 2.5666 / 50 = 0.051332

Insert the value of k in eqn (ii);

t1/2 = ln(2) / k

t1/2 = 0.693 / 0.051332 = 13.5 years

4 0
3 years ago
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