Is the value of the 1 in 1,440,000 10 times as great as the value of the 4 in the hundred thousands place ? Explain

Mathematics

1 answer:

Burka [1]3 years ago

7 0

I do not think so, because it has to be the same number.
Ex: 5,539 - in this the 5 in the thousands place is greater than the 5 in the hundreds place

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If the sales tax in Maple Town is 9.5%, how much would an ice cream of $4.25 cost with the tax added? Please explain.

faltersainse [42]

To find the sales tax, you need to find 9.5% of 4.25

4.25*.095 = <span>.40375

Now we need to add the sales tax to the price.

4.25 + </span>.40375 = <span>4.65375
Because dollars one have 2 decimal points we should round this to 4.65

Hope this helped!
</span>

5 0

3 years ago

Read 2 more answers

A field with an area of 2880 ft^2 has the shape of a rectangle, whose length is 12 ft larger than its width. Find the dimensions

tiny-mole [99]

ANSWER

w=48,l=60

EXPLANATION

Let the width of the field be, w , then,

the length of the field will be:

$l = 12 + w$

The area of a rectangle is

$Area = lw$

This implies that:

$w(12 + w) = 2880$

Expand

${w}^{2} + 12w = 2880$

${w}^{2} + 12w - 2880 = 0$

$(x + 60)(x - 48) = 0$

This implies that,

$w = - 60 \: w = 48$

The dimensions are positive, the width is 48 and the length is 12+48=60

8 0

3 years ago

The sum of four times a number and five times another number is -28. The sum of nine times the first number and two times the se

Rina8888 [55]

Answer:

Step-by-step explanation:

$x,\ y-the\ numbers\\\\\text{The sum of four times a number and five times another number is -28:}\\\\4x+5y=-28\\\\\text{The sum of nine times the first number and two times the second number is 11:}\\\\9x+2y=11\\\\\text{We have the system of equations:}\\\\\left\{\begin{array}{ccc}4x+5y=-28&\text{multiply both sides by2}\\9x+2y=11&\text{multiply both sides by (-5)}\end{array}\right\\\\\underline{+\left\{\begin{array}{ccc}8x+10y=-56\\-45x-10y=-55\end{array}\right}\qquad\text{add both sides of the equation}$

$.\qquad-37x=-111\qquad\text{divide both sides by (-37)}\\.\qquad\qquad\boxed{x=3}\\\\\text{Put the value of x to the first equation:}\\\\4(3)+5y=-28\\12+5y=-28\qquad\text{subtrac 12 from both sides}\\5y=-40\qquad\text{divide both sides by 5}\\\boxed{y=-8}$