√896z^15/<span>√225z^6
= </span>√896z^9/<span>√225
= </span>√64√14(z^4)<span>√z/15
= 8</span>√14(z^4)<span>√z/15
= (8z^4/15) * </span><span>√14z
x = 8</span>
The value of y-x is (-3)
<u>Solution:</u>
Given: The value of x-y=3
To find: The value of y-x

Let's multiply the equation (1) by (- 1) on both sides,


On multiplying the sign,

The above equation can also be written as,

<u>Multiplication of signs:</u>




In simpler terms, when we multiply two integers with the same signs, the result is always positive and when we multiply two integers with different signs, the result is always negative.
Answer:
7√2 units
Step-by-step explanation:
The distance between two points having coordinates (x1, y1) and (x2, y2) is given by,

Here, x1=-4 and y1=2
x2=3 and y2=-5




Well there really wouldn't be a combo since everything is different so I'm saying nun? that's what I'm going with. ( If this is wrong correct me )