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evablogger [386]
3 years ago
10

What is the image of (6,−3) after a dilation by a scale factor of 1/3 centered at the origin?

Mathematics
1 answer:
attashe74 [19]3 years ago
6 0

Answer:

(2,-1)

Step-by-step explanation:

Multiply everything by 1/3:

6*1/3=2

-3*1/3=-1

This makes it smaller, so you know what the dilation is.

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Oliga [24]
Answer is below..............

7 0
3 years ago
Average precipitation for the first 7 months of the year, the average precipitation in toledo, ohio, is 19.32 inches. if the ave
Colt1911 [192]
Part A:

The probability that a normally distributed data with a mean, μ and standard deviation, σ is greater than a given value, a is given by:

P(x\ \textgreater \ a)=1-P(x\ \textless \ a)=1-P\left(z\ \textless \  \frac{a-\mu}{\sigma}\right)

Given that the average precipitation in Toledo, Ohio for the past 7 months is 19.32 inches with a standard deviation of 2.44 inches, the probability that <span>a randomly selected year will have precipitation greater than 18 inches for the first 7 months is given by:

P(x\ \textgreater \ 18)=1-P(x\ \textless \ 18) \\  \\ =1-P\left(z\ \textless \ \frac{18-19.32}{2.44}\right) \\  \\ =1-P(z\ \textless \ -0.5410) \\  \\ =1-0.29426=\bold{0.7057}



Part B:

</span>The probability that an n randomly selected samples of a normally distributed data with a mean, μ and standard deviation, σ is greater than a given value, a is given by:

P(x\ \textgreater \ a)=1-P(x\ \textless \ a)=1-P\left(z\ \textless \ \frac{a-\mu}{\frac{\sigma}{\sqrt{n}}}\right)

Given that the average precipitation in Toledo, Ohio for the past 7 months is 19.32 inches with a standard deviation of 2.44 inches, the probability that <span>5 randomly selected years will have precipitation greater than 18 inches for the first 7 months is given by:

</span>P(x\ \textgreater \ 18)=1-P(x\ \textless \ 18) \\ \\ =1-P\left(z\ \textless \ \frac{18-19.32}{\frac{2.44}{\sqrt{5}}}\right) \\ \\ =1-P(z\ \textless \ -1.210) \\ \\ =1-0.1132=\bold{0.8868}
7 0
3 years ago
Jay ate 2/3 of a pizza. Dan ate 4 times the amount of jay ate . How much did dan eat
erica [24]

Answer:

Dan eat 2\frac{2}{3} pizzas

Step-by-step explanation:

Let

x-----> amount of pizza Jay ate

y-----> amount of pizza Dan ate

we know that

x=\frac{2}{3} ----> equation A

y=4x -----> equation B

substitute equation A in the equation B and solve for y

y=4(\frac{2}{3})=\frac{8}{3}

Convert to mixed number

\frac{8}{3}=\frac{6}{3}+\frac{2}{3}=2\frac{2}{3}

8 0
3 years ago
A space shuttle is scheduled to launch from Kennedy Space Center on Friday morning. If it is raining, the launch will be delayed
goldfiish [28.3K]
Likely could be  the answer
8 0
3 years ago
PLEASE HELP ASAP WILL GIVE BRAINLIEST !!!
My name is Ann [436]

Answer:

7/3

Step-by-step explanation:

7/3

8 0
3 years ago
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