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Aloiza [94]
3 years ago
14

–14, –7, 0, 7, 14, … Find the 19th term…

Mathematics
1 answer:
Alexus [3.1K]3 years ago
7 0
-14,-7,0,7,15....this is an arithmetic sequence with a common difference of 7.

an = a1 + (n-1) * d
n = term to find = 19
a1 = first term = -14
d = common difference = 7
time to sub and solve :)

a(19) = -14 + (19 - 1) * 7
a(19) = -14 + 18 * 7
a(19) = -14 + 126
a(19) = 112 <===
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5 Erasers, 4:1 is equal to 20:5, if you just multiply both numbers by 5
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3 years ago
Read 2 more answers
true or false If x represents a random variable with mean 114 and standard deviation 40, then the standard deviation of the samp
Goshia [24]

Answer:

\mu = 114, \sigma = 40

We also know that we select a sample size of n =100 and on this case since the sample size is higher than 30 we can apply the central limit theorem and the distribution for the sample mean would be given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And the standard deviation for the sampling distribution would be:

\sigma_{\bar X}= \frac{40}{\sqrt{100}}= 4

So then the answer is TRUE

Step-by-step explanation:

Let X the random variable of interest and we know that the true mean and deviation for this case are given by:

\mu = 114, \sigma = 40

We also know that we select a sample size of n =100 and on this case since the sample size is higher than 30 we can apply the central limit theorem and the distribution for the sample mean would be given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And the standard deviation for the sampling distribution would be:

\sigma_{\bar X}= \frac{40}{\sqrt{100}}= 4

So then the answer is TRUE

6 0
3 years ago
Prove the sum of two rational numbers is rational where a, b, c, and d are integers and b and d cannot be zero. Fill in the miss
mario62 [17]

Answer:

We conclude that the sum of two rational numbers is rational.

Hence, the fraction will be a rational number. i.e.

  • \frac{ad+cb}{bd}       ∵ b≠0, d≠0, so bd≠0

Step-by-step explanation:

Let a, b, c, and d are integers.

Let a/b and c/d are two rational numbers and b≠0, d≠0

Proving that the sum of two rational numbers is rational.

\frac{a}{b}+\frac{c}{d}

As the least common multiplier of b, d: bd

Adjusting fractions based on the LCM

\frac{a}{b}+\frac{c}{d}=\frac{ad}{bd}+\frac{cb}{db}

\mathrm{Since\:the\:denominators\:are\:equal,\:combine\:the\:fractions}:\quad \frac{a}{c}\pm \frac{b}{c}=\frac{a\pm \:b}{c}

          =\frac{ad+cb}{bd}

As b≠0, d≠0, so bd≠0

Therefore, we conclude that the sum of two rational numbers is rational.

Hence, the fraction will be a rational number. i.e.

  • \frac{ad+cb}{bd}       ∵ b≠0, d≠0, so bd≠0
3 0
3 years ago
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Lelechka [254]

Answer: I am pretty sure it is y=-1/4x-8. Hope this helps!

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Levart [38]

Answer:

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Step-by-step explanation:

In order to find the ratio between the total puppies to brown puppies we need to take the total amount of puppies , that is, the sum of all the puppies and divide it by the number of brown puppies. So we have:

ratio  = total amount of puppies/brown puppies

ratio  = (3+2+1)/(2) = 6/2 = 3/1

The ratio is for every three puppies we have one brown puppie.

8 0
3 years ago
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