Full Question
A 10 kilogram object suspended from the end of a vertically hanging spring stretches the spring 9.8 centimeters. At time t = 0, the resulting mass—spring system is disturbed from its rest state by the force F (t) = 20 cos(8t). The force F (t) is expressed in Newtons and is positive in the downward direction, and time is measured in seconds.
Determine the spring constant k.
Answer:
Spring Constant = 1000Nm^-1
Step-by-step explanation:
Given
Mass = 10kg
Spring Extension = 9.8cm
Spring Constant K = Force/Extension
Force = Mass * Acceleration
Force = 10 * 9.8 = 9.8N
Spring Extension = 9.8 cm = 9.8 /100 = 0.098 m
Spring constant = 98 / 0.098
Spring Constant = 1000Nm^-1
The answer is $12,052.5. youd divide 800 into 1500 then you multiply the answer you get by 6400 then add (1500/100) x 3.5 to get your answer.
Answer:
Step-by-step explanation:
Area of parallelogram=base*height
So 1.75*1.5=2.625cm²
Answer:
a
Step-by-step explanation:
6^2+8^2=100
sqrt of 100 = 10
Answer:
3.5 m/s²
Step-by-step explanation:
We are given;
- The force of a bicycle as 3.5 × 10² N
- Mass of the bicycle as 1.0 × 10² kg
We are required to determine the acceleration of the bicycle;
From Newton's second law of motion;
F = ma
Rearranging this;
a = F÷ m
Therefore;
Acceleration = 3.5 × 10² N ÷ 1.0 × 10² kg
= 3.5 m/s²
Thus, the acceleration of the bicycle is 3.5 m/s²
