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IceJOKER [234]
3 years ago
11

1) The graph of a bicycle ramp contains the points (-6,0) and (3,3). What is 5 points

Mathematics
1 answer:
lianna [129]3 years ago
6 0

Answer:

\frac{1}{3}

Step-by-step explanation:

It was given that, the graph of the bicycle ramp contains the points (-6,0) and (3,3).

We want to find the slope.

We use the formula:

m =  \frac{y_2-y_1}{x_2-x_1}

We substitute the points into the formula to get;

m =  \frac{3 - 0}{3 -  - 6}

m =  \frac{3}{3 + 6}

Add in the denominator

m =  \frac{3}{9}  =  \frac{1}{3}

The slope of the ramp is 1/3.

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#2).    113.04

Step-by-step explanation:

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What are the zeros of the polynomial function?
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7 0
3 years ago
Someone help me with what p and q equals?
nevsk [136]
Q = 6 and p = 5

It’s a parallelogram so the side opposite are the same.

6 = q - 3
Subtract 3 and add it to 6 and you get 9
9=q
5 0
2 years ago
A quadrilateral has vertices A(3, 5), B(2, 0), C(7, 0), and D(8, 5). Which statement about the quadrilateral is true?
Aleksandr-060686 [28]

Answer: A quadrilateral has vertices A(3, 5), B(2, 0), C(7, 0), and D(8, 5). Find:

You can see that vectors and This means that opposite sides are parallel and option B is false.

Find the lengths of all sides:

As you can see the lengths of opposite sides are equal, but all lengths are not equal. Therefore, the last option D is false.

Now check whether angles A and B are perpendicular:

The dot products are not equal to zero, then angles A and B are nor right. This means that option C is false and option A is correct (ABCD is a parallelogram with non-perpendicular adjacent sides

AKA your correct awnser choice is A :)✨

5 0
3 years ago
ABCD- parallelogram, If the perimeter of Triangle CPQ is 15cm, Find the perimeter of triangle BAQ. Find the perimeter of triangl
melamori03 [73]

Answer:

The answer is below

Step-by-step explanation:

A parallelogram is a quadrilateral (has 4 sides and 4 angle) with two pair of parallel and opposite sides. Opposite sides of a parallelogram are parallel and equal.

Given parallelogram ABCD:

AB = CD = 18 cm; BC = AD = 8 cm

∠P = ∠P, ∠PDA = ∠PCQ (corresponding angles are equal).

Hence ΔPCQ and ΔPDA are similar by angle-angle similarity theorem. For similar triangles, the ratio of their corresponding sides equal. Therefore:

\frac{CD}{PC}= \frac{AD}{CQ}\\\\\frac{18}{6}=\frac{8}{x}  \\\\x=\frac{6*8}{18}=\frac{8}{3}\ cm

Perimeter of CPQ = CP + CQ + PQ

15 = 6 + 8/3 + PQ

PQ = 15 - (6 + 8/3)

PQ = 6.33

∠CQP = ∠AQB (vertical angles), ∠QCP = ∠QBA (alternate angles are equal).

Hence ΔCPQ and ΔABQ are similar by angle-angle similarity theorem

\frac{AQ}{QP}=\frac{AB}{CP}  \\\\\frac{AQ}{6.33} =\frac{18}{6} \\\\AQ=\frac{18}{6}*6.33\\\\AQ = 19

\frac{BQ}{CQ}=\frac{AB}{CP}  \\\\\frac{BQ}{8/3} =\frac{18}{6} \\\\BQ=\frac{18}{6}*\frac{8}{3} \\\\BQ =8

Perimeter of BAQ = AB + BQ + AQ = 18 + 8 + 19 = 45cm

PA = AQ + PQ = 19 + 6.33 = 25.33

PD = CD + DP = 18 + 6 = 24

Perimeter of PDA = PA + PD + AD = 24 + 25.33 + 8 = 57.33 cm

7 0
3 years ago
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