Hey,
I could actually answer the question now, so I am going to put it here as well so the people don't have to read the comments above.
<span>Use the Pythagorean Theorem to find the hypotenuse:<span>a² + b² = c²
5² + 5² = c²
25 + 25 = c²
50 = c²
√50=√(c^2 )
7.07 = c
Answer: 7
Cheers,
Izzy</span></span>
Factor
(x+7)(x-2)
Proof
7-2=5
7*-2=-14
Zeros
x+7=0
x=-7
x-2=0
x=2
Final answer: C
In the 
plane, we have 
everywhere. So in the equation of the sphere, we have
which is a circle centered at (2, -10, 0) of radius 4.
In the 
plane, we have 
, which gives
But any squared real quantity is positive, so there is no intersection between the sphere and this plane.
In the 
plane, 
, so
which is a circle centered at (0, -10, 3) of radius 
.
3x3x3x3 = 81
x.x.x.x = x^4
2x2x2x2 = 16
B. 81x^4/16
