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Leno4ka [110]
3 years ago
6

What is the circumference of the circle below? (Round your answer to the nearest tenth.)

Mathematics
1 answer:
yuradex [85]3 years ago
3 0

Answer:

D

Step-by-step explanation:

Circumference of circle = 2πr

r = 9cm

Circumference of circle = 2×9×3.142

Circumference of circle = 56.5cm

You might be interested in
Graph for f(x)=6^6 and f(x)=14^x
zlopas [31]

Graph Transformations

There are many times when you’ll know very well what the graph of a

particular function looks like, and you’ll want to know what the graph of a

very similar function looks like. In this chapter, we’ll discuss some ways to

draw graphs in these circumstances.

Transformations “after” the original function

Suppose you know what the graph of a function f(x) looks like. Suppose

d 2 R is some number that is greater than 0, and you are asked to graph the

function f(x) + d. The graph of the new function is easy to describe: just

take every point in the graph of f(x), and move it up a distance of d. That

is, if (a, b) is a point in the graph of f(x), then (a, b + d) is a point in the

graph of f(x) + d.

As an explanation for what’s written above: If (a, b) is a point in the graph

of f(x), then that means f(a) = b. Hence, f(a) + d = b + d, which is to say

that (a, b + d) is a point in the graph of f(x) + d.

The chart on the next page describes how to use the graph of f(x) to create

the graph of some similar functions. Throughout the chart, d > 0, c > 1, and

(a, b) is a point in the graph of f(x).

Notice that all of the “new functions” in the chart di↵er from f(x) by some

algebraic manipulation that happens after f plays its part as a function. For

example, first you put x into the function, then f(x) is what comes out. The

function has done its job. Only after f has done its job do you add d to get

the new function f(x) + d. 67Because all of the algebraic transformations occur after the function does

its job, all of the changes to points in the second column of the chart occur

in the second coordinate. Thus, all the changes in the graphs occur in the

vertical measurements of the graph.

New How points in graph of f(x) visual e↵ect

function become points of new graph

f(x) + d (a, b) 7! (a, b + d) shift up by d

f(x) Transformations before and after the original function

As long as there is only one type of operation involved “inside the function”

– either multiplication or addition – and only one type of operation involved

“outside of the function” – either multiplication or addition – you can apply

the rules from the two charts on page 68 and 70 to transform the graph of a

function.

Examples.

• Let’s look at the function • The graph of 2g(3x) is obtained from the graph of g(x) by shrinking

the horizontal coordinate by 1

3, and stretching the vertical coordinate by 2.

(You’d get the same answer here if you reversed the order of the transfor-

mations and stretched vertically by 2 before shrinking horizontally by 1

3. The

order isn’t important.)

74

7:—

(x) 4,

7c’

‘I

II

‘I’

-I

5 0
3 years ago
a group of friends shared 3 rolls of clay equally. if each student gor 1/2 of a roll of clay, how many students were in the grou
klemol [59]
6 students – 3 rolls of clay divided by each portion given to a student (0.5) equals 6, meaning only six students where able to receive some clay

8 0
3 years ago
Complete the equation of the line through (-6,-5)(−6,−5)(, minus, 6, comma, minus, 5, )and (-4,-4)(−4,−4)(, minus, 4, comma, min
alina1380 [7]

Answer:

y=\frac{1}{2}x-2

Step-by-step explanation:

We have been given two points on a line (-6,-5) and (-4,-4). We are asked to write an equation passing through these points.

We will write our equation in slope-intercept form of equation y=mx+b, where,

m = Slope of line,

b = Initial value or the y-intercept.

Let us find slope of given line using slope formula.

m=\frac{y_2-y_1}{x_2-x_1}

Let point (-6,-5)=(x_1,y_1) and point (-4,-4)=(x_2,y_2).

m=\frac{-4-(-5)}{-4-(-6)}

m=\frac{-4+5}{-4+6}

m=\frac{1}{2}

Now, we will substitute m=\frac{1}{2} and coordinates of point (-6,-5) in slope-intercept form of equation as:

-5=\frac{1}{2}*(-6)+b

-5=-3+b

-5+3=-3+3+b

-2=b

Upon substituting m=\frac{1}{2} and b=-2 in slope-intercept form of equation, we will get our required equation as:

y=\frac{1}{2}x-2

Therefore, our required equation would be y=\frac{1}{2}x-2.

8 0
3 years ago
if a number is increased by 5 and the result is then divided by three,the result is seven. write an equation that models this ve
gregori [183]
A number (we don’t know the number so I’ll use X) plus five. So we can start the equation of with X+5 then divided by 3=7 so X+5➗3=7 so to solve what X is we can just go in reverse. 7 TIMES 3= 21-5=16 so X=16
6 0
3 years ago
Read 2 more answers
Please help me, I have no idea what the equation for the new path is. <br><br> Thank you!!
Citrus2011 [14]
First, find the slope of the initial line; 

m=(y₁-y₂)/(x₁-x₂) 

m=(4-0)/(11-8) 
m=4/3 

If two lines are parallel, the slope is the same although the intercept can differ. 

If this parallel lines passes through the point (4, 5); 

y=(4/3)x+c <-- plug in coordinates to solve for c
5=(4/3)(4)+c 
(15/3)=16/3+c 
(15/3)-(16/3)=c 
-1/3=c 

Therefore, the final equation should be y=4/3x-1/3

Hope I Helped :) 
8 0
3 years ago
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