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Dennis_Churaev [7]
3 years ago
6

How many steps do we take from 0 to -13???

Mathematics
1 answer:
Rus_ich [418]3 years ago
6 0

Answer:

13

Step-by-step explanation:

because thats how u get to 13

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A cylindrical swimming pool has a diameter of 16 feet and a height of 3 feet. How many gallons of water can the pool contain? Ar
kiruha [24]

Answer:

The pool can contain <u>4521.6 gallons</u> of water.

Step-by-step explanation:

Given:

The diameter of the cylindrical swimming pool = 16 feet.

And the height of the cylindrical swimming pool = 3 feet.

(1 ft³ = 7.5 gallons)

Now, to find the gallons of water the pool can contain.

So, we find the radius first:

Radius (r) = \frac{Diameter}{2} = \frac{16}{2} =8\ feet.

Height (h) = 3 feet.

Now, to get the volume of swimming pool which is cylindrical in shape by putting formula (using the value of π = 3.14):

Volume=\pi r^2h

Volume=3.14\times 8^2\times 3

Volume=3.14\times 64\times 3

Volume=602.88\ feet^3.

<em>Thus, getting the volume of pool 602.88 feet³.</em>

<em>As, given 1 ft³ = 7.5 gallons</em>.

Now, to get the gallons of water the pool can contain we multiply the volume of pool by 7.5:

602.88\times 7.5

=4521.6\ gallons.

Therefore, the pool can contain <u>4521.6 gallons</u> of water.

7 0
3 years ago
I'm so confused
kirza4 [7]

Answer: 16............................

5 0
2 years ago
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Anyone know how to solve this?
yuradex [85]

Answer:

<h2>\frac{16}{25}</h2>

Step-by-step explanation:

<h3>( -  \frac{4}{5})^{2}</h3><h3>{( - 1)}^{2}  \frac{ {4}^{2} }{ {5}^{2} }</h3><h3>1 \frac{ {4}^{2} }{ {5}^{2} }</h3><h3>\frac{ {4}^{2} }{ {5}^{2} }</h3><h3>\frac{16}{25}</h3><h3>Hope it is helpful....</h3>
5 0
3 years ago
Please answer these questions
lianna [129]

Answer:

8.  -3, 16

9.  -3, 4.5

Step-by-step explanation:

See attached worksheet.

4 0
1 year ago
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Find the length of side x in simplest radical form with rational denominator.
DaniilM [7]

Answer:

sqrt(20)

Step-by-step explanation:

The two perpendicular side lengths are equal, so using Pythagoras theorem:

x = sqrt( sqrt(10)^2 + sqrt(10)^2 )

x = sqrt(10 + 10)

x = sqrt(20)

8 0
3 years ago
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