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3 years ago

I’ll mark u as brainliest

Mathematics

2 answers:

krek1111 [17]3 years ago

8 0

Answer:

8,20,32

Step-by-step explanation:

You would do 2 x 4 and so on

Olenka [21]3 years ago

7 0

Answer:

8,20,32

Step-by-step explanation:

multiply 4 times each number in the x section

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Which of the following statements is true?

julia-pushkina [17]

A) A triangle can have two congruent angles.
It's called an Isosceles Triangle

5 0

4 years ago

15 mm<br>9 mm<br>12 mm<br>What is the area

s2008m [1.1K]

Answer:

i dont know man ask your teacher

Step-by-step explanation:

i aint got any steps bro

7 0

3 years ago

The probability that the noise level of a wide-band amplifier will exceed 2 dB is 0.05 independently of every other amplifier. C

snow_lady [41]

Answer:

0.980

Step-by-step explanation:

The probability that the noise level of a wide-band amplifier will exceed 2 dB is 0.05

So, probability of success = 0.05

Probability of failure = 1-0.05=0.95

There are 12 amplifiers

We are supposed to find the probability that at most two will exceed 2dB.

We will use binomial distribution

Formula : $P(X=r)=^nC_r p^r q ^{n-r}$

p = 0.05

q = 0.95

n = 12

We are supposed to find the probability that at most two will exceed 2dB.

So, $P(X\leq 2)=P(X=0)+P(X=1)+P(X=2)$

$P(X\leq 2)=^{12}C_0 P(0.05)^0 (0.95)^{12-0}+^{12}C_1 P(0.05)^1(0.95)^{12-1}+^{12}C_2 P(0.05)^2 (0.95)^{12-2}$

$P(X\leq 2)=\frac{12!}{0!(12-0)!} (0.05)^0 (0.95)^{12-0}+\frac{12!}{1!(12-1)!}(0.05)^1(0.95)^{12-1}+\frac{12!}{2!(12-2)!} (0.05)^2 (0.95)^{12-2}$

$P(X\leq 2)=0.980$

Hence the probability that at most two will exceed 2dB is 0.980

7 0

3 years ago

Describe the difference between algebraic expressions and numerical expressions.

Mila [183]

The difference between an algebraic expression and a numerical expression is that algebraic expressions contain numbers and variables. Numerical expressions only contain numbers.

Ex:
Algebraic Expression- 5x+9
Numerical Expression- 4+2

7 0

3 years ago

We have a bilateral triangle with base length 2 and sidelengths x where x is increasing at a rate

BaLLatris [955]

Answer:

$\frac{5\sqrt{3} }{6}$

Step-by-step explanation:

Given :

base length = 2

side lengths = x

dx/dt = 5 unit/min

Determine d∅ / dt at x = 2

d∅ / dt at x = 2 = $\frac{5\sqrt{3} }{6}$

attached below is a detailed solution

7 0

3 years ago