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DIA [1.3K]
3 years ago
6

I need to know how to work this problem out and get the answer

Mathematics
1 answer:
KiRa [710]3 years ago
3 0
What is the problem?
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PLEASE HELP ME PLEASE HELP ME PLEASE HELP ME PLEASE HELP ME PLEASE HELP ME
fredd [130]
You answer would be -4,-5 because you got to look where there line cross
4 0
3 years ago
What’s the width? Please help ASAP
just olya [345]

Answer:

9 and 4 or D

Step-by-step explanation:

If you're not quite sure how to solve, let's find the answer by process of elimination.

If the area of a rectangle is 36 square inches, we can try option one.

7 * 6 = 42, not 36, so option A is incorrect.

Option two:

12 * 3 = 36 so option B is correct.

Option 3:

10 * 3 = 30 so option C is incorrect

Option 4:

9 * 4 = 36 so option D is correct

Now for perimeter:

9 + 4 + 9 + 4 = 18 + 8 = 26.

12 + 12 + 3 + 3 = 24 + 6 = 30

Thus, an answer of 9 and 4 is correct.

3 0
3 years ago
What do they call a number that goes on forever?
Art [367]
I believe they call it a recurring number, for example, infinity is a recurring number.
3 0
3 years ago
Read 2 more answers
HELP I NEED HELP ASAP
Kaylis [27]

Answer:

so how many units are they away from each other

Step-by-step explanation:1,

1.1-2.0  how many units are they away from each other

u could drag the number from the top to the chart below

good luck!

6 0
3 years ago
yLab and Mastering3.3.43Question HelpIn triangle ABC, the measure of angle Bis 15 more than three times the measure of angle A.
lora16 [44]

∠A = 24°

∠B = 87°

∠A = 24°

Explanation:

The sum of angles in a triangle is 180 degrees

let measure of angle A = ∠A

∠B = 15 more than three times the measure of angle A

∠B = 15 + 3∠A

∠C = 45° more than the measure of angle A

∠C = 45° + ∠A

∠A + ∠B + ∠C = 180° (sum of angles in a triangle)

∠A + 15 + 3∠A + 45° + ∠A = 180

collect like terms:

∠A + 3∠A + ∠A + 15 + 45 = 180

5∠A + 60 = 180

5∠A = 180 -60

5∠A = 120

∠A = 120/5

∠A = 24°

∠B = 15 + 3∠A = 15 + 3(24)

∠B = 87°

∠C = 45° + ∠A = 45° + 24°

∠C = 69°

8 0
1 year ago
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