What is 0.000099 in scientific notation??

In a group of 40 people, 27 can speak English and 25 can speak Spanish. How many can speak

Svetradugi [14.3K]

$\qquad {\: \:\bigstar \: {\underline{\overline{\boxed{\bf{Information \: provided \: with \: us }}}}}\: \bigstar}$

➻ In a group of 40 people, 27 can speak English and 25 can speak Spanish.

$\qquad {\: \:\bigstar \: {\underline{\overline{\boxed{\bf{What \: we \: have \: to \: find ? }}}}}\: \bigstar}$

➻ The required number of people who can speak both English and Spanish .

$\qquad {\: \:\bigstar \: {\underline{\overline{\boxed{\bf{Assumption}}}}}\: \bigstar}$

Consider ,

➻ A → Set of people who speak English.

➻ B → Set of people who speak Spanish

➻ A∩B → Set of people who can speak both English and Spanish

$\qquad {\: \:\bigstar \: {\underline{\overline{\boxed{\bf{Given}}}}}\: \bigstar}$

➻ n (A) = 27

➻ n (B) = 25

➻ n (A∪B) = 40

➻ n(A∩B) = ?

$\qquad {\: \:\bigstar \: {\underline{\overline{\boxed{\bf{Now}}}}}\: \bigstar}$

➻ n(A∪B) = n(A) + n (B) - n(A∩B)

➻ 40 = 27 + 25 - n (A∩B)

➻ 40 = 52 - n (A∩B)

➻ n (A∩B) = 52 - 40

➻ ∴ n (A∩B) = 12

$\qquad {\: \:\bigstar \: {\underline{\overline{\boxed{\bf{Therefore}}}}}\: \bigstar}$

∴ Required Number of persons who can speak both English and Spanish are 12 .

━━━━━━━━━━━━━━━━━━━━━━

$\qquad {\: \:\bigstar \: {\underline{\overline{\boxed{\bf{Verification}}}}}\: \bigstar}$

➻ n(A∪B) = n(A) + n (B) - n(A∩B)

➻ 40 = 27 + 25 - 12

➻ 40 = 52 - 12

➻ 40 = 40

➻ ∴ L.H.S = R.H.S

━━━━━━━━━━━━━━━━━━━━━━

6 0

2 years ago

Use the distance formula to answer the question: What is the distance between (5,9), (1, 6)?

joja [24]

Step-by-step explanation:

The formula is Distance=√(x2-x1)²+(y2 -y1)²

x1 is 5, x2 is 1, y1 is 9, y2 is 6

D = √( 1-5)² +(6-9)²

D = √(-4)²+(-3)²

D = √16+9

D = √25

D = 5 units

3 0

2 years ago

1. (SLO) Simplify the expression: 6(b-7)

Sav [38]

1 → B

multiply each term in the parenthesis by the 6 outside

6(b-7) = 6b - 42

2 → D

multiply each term in the parenthesis by the 3 outside

3(4x+6y+2) = 12x+18y+6

3 → A

the value outside the parenthesis is -1, hence each term inside is multiplied by -1

-1(6x+5y) = -6x -5y

3 0

3 years ago

Read 2 more answers

6x-4y=8 solve for variable x

Radda [10]

6x - 4y = 8...solve for x
6x = 4y + 8
x = (4/6)y + 8/6
x = 2/3y + 4/3 <==

8 0

3 years ago

Determine whether the relation R on the set of all Web pages is reflexive, symmetric, antisymmetric, and/or transitive, where (a

xxMikexx [17]

Answer:

a) R is reflexive, R is not symmetric, R is not anti-symmetric, R is transitive.

b) R is reflexive, R is symmetric, R is not anti-symmetric, R is not transitive.

c) R is not reflexive, R is symmetric, R is not anti-symmetric, R is not transitive.

Step-by-step explanation:

a)

(a, b) ∈ R if and only if everyone who has visited Web page a has also visited Web page b.

Obviously R is reflexive (aRa)

Everyone who has visited Web page a has also visited Web page a

R is not symmetric (aRb does not imply bRa)

If everyone who has visited Web page a has also visited Web page b does not mean that everyone who has visited Web page b has also visited Web page a

R is not anti-symmetric (aRb and bRa does not imply a=b)

If everyone who has visited Web page a has also visited Web page b and everyone who has visited Web page b has also visited Web page a does not mean the web pages are the same.

R is transitive (aRb and bRc implies aRc)

If everyone who has visited Web page a has also visited Web page b and everyone who has visited Web page b has also visited Web page c implies that everyone who has visited Web page a has also visited Web page c.

b)

(a, b) ∈ R if and only if there are no common links found on both Web page a and Web page b.

R is obviously reflexive (aRa)

R is symmetric (aRb implies bRa)

if there are no common links found on both Web page a and Web page b, then there are no common links found on both Web page b and Web page a.

R is not anti-symmetric (aRb and bRa does not imply a=b)

if there are no common links found on both Web page a and Web page b and there are no common links found on both Web page b and Web page a does not mean a and b are the same web page.

R is not transitive (aRb and bRc does not imply aRc)

Consider for example three web pages a, b and c such that a and c have a common link and b has no external links at all.

Then obviously (a,b)∈R and (b,c)∈R since b has no links, but (a,c)∉R because they have a common link.

c)

(a, b) ∈ R if and only if there is at least one common link on Web page a and Web page b

R is not reflexive

If the web page a does not have any link at all, then a is not related to a.

R is symmetric (aRb implies bRa)

if there is at least one common link found on Web page a and Web page b, then there is at least one common link found on Web page b and Web page a.

R is not anti-symmetric (aRb and bRa does not imply a=b)

if there is at least one common link found on Web page a and Web page b and there is at least one common link found on Web page b and Web page a does not mean the web pages are the same

R is not transitive (aRb and bRc does not imply aRc)

Consider for example three web pages a, b and c such that a has only two links L1 and L2, b has only two links L2 and L3 c has only two links L3 and L4.

Then (a, b) ∈ R since a and b have the common link L2, (b, c) ∈ R for b and c have the common link L3, but a and c have no common links, therefore (a,c)∉R

5 0

3 years ago