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sattari [20]
3 years ago
5

What is 0.000099 in scientific notation??

Mathematics
1 answer:
Lerok [7]3 years ago
7 0
The answer would be 99, because because if you remove the decimals and the 0's you get 99.

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he diameter of an ice skating rink is 44 feet. In terms of π, what is the area of the rink to the nearest square yard? (9 ft2 =
crimeas [40]

Answer:

The area of the circular ring is 53.73 π  sq. yards

Step-by-step explanation:

The diameter of the skating ring = 44 ft

Diameter =  2 x Radius

⇒Radius of the ring  = 44 / 2  = 22 ft

Now, 1 ft = 0.333333 yards

⇒22 ft  = 22 x 0.333333 yards = 7.3333 yards

Now, Area of the circular Ring = \pi r^2\\

or, A = \pi (7.33)^2

=  53.73 π  sq. yards

or, the area of the circular ring is 53.73 π  sq. yards

6 0
3 years ago
Evaluate tan45/sin30 . In your final answer, include all calculations.
Maslowich
From the identity \displaystyle{ \tan x= \frac{\sin x}{\cos x}, and from the values:

                 \sin45^{\circ}=\cos45^{\circ}= \frac{ \sqrt{2}}{2},

we have: \displaystyle{ \tan 45^{\circ}= \frac{\sin 45^{\circ}}{\cos 45^{\circ}}= \frac{ \frac{ \sqrt{2}}{2}}{\frac{ \sqrt{2}}{2}} =1.


We also know that \sin30^{\circ}= \frac{1}{2}.


Thus, \displaystyle{  \frac{\tan 45^{\circ}}{\sin30^{\circ}} = \frac{1}{\frac{1}{2}}=2.



Answer: 2
8 0
3 years ago
The sum of a number and twice its reciprocal is 3. What are the numbers?
qwelly [4]

Let no be x

Acc to ques

X + 2(1/x) = 3

X + 2/x = 3

X^2 + 2 = 3x

X^2 - 3x + 2 = 0

X^2 - x - 2x + 2 = 0

X (x-1) - 2 (x-1) = 0

(x-2) (x-1) = 0

X= 2 or x =1

If this answer was helpful then please mark it as the brianliest

3 0
3 years ago
These are the answers. <br> yes they are correct.
gregori [183]

Answer:

I'm confused are you asking if your answer is correct

Step-by-step explanation:

4 0
3 years ago
A ball with mass m kg is thrown upward with initial velocity 28 m/s from the roof of a building 17 m high. Neglect air resistanc
Nutka1998 [239]

a. At its maximum height, the ball has zero vertical velocity, so

-\left(28\dfrac{\rm m}{\rm s}\right)^2=2(-g)(y_{\rm max}-17\,\mathrm m)

\implies y_{\rm max}=57\,\mathrm m

b. The ball's height in the air y at time t is given according to

y=17\,\mathrm m+\left(28\dfrac{\rm m}{\rm s}\right)t-\dfrac g2t^2

Solve for t when y=0:

17+28t-4.9t^2=0\implies t\approx6.3\,\mathrm s

3 0
3 years ago
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