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Katen [24]
3 years ago
5

Metal surfaces on spacecraft in bright sunlight develop a net electric charge.

Physics
1 answer:
koban [17]3 years ago
5 0

Answer:

Positive.

Explanation:

As a consequence of the photoelectric effect, electrons that will get hit by sufficiently energetic photons will abandon the metal surfaces exposed to bright sunlight. This decreases the negative charge of the surface, thus causing it to develop a positive net charge.

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The acceleration of a particle is given by a = 3t – 4, where a is in meters per second squared and t is in seconds. Determine th
Genrish500 [490]

Answer:

v=0.04m/s\\

s=-28.592m\\

Explanation:

a = 3t-4

v(t)=\int\limits^t_0 {a(t)} \, dt =3/2*t^{2}-4t+v_0\\

if t=3.6s and initial velocity, v0,  is -5m/s

v=0.04m/s\\

s(t)=\int\limits^t_0 {v(t)} \, dt =1/2*t^{3}-2t^{2}+v_0*t+s_0\\

if t=3.6s and the initial displacement, s0, is -8m:

s=-28.592m\\

5 0
3 years ago
Why are magnetic fields evidence of sea floor spreading
xenn [34]
Eruptions of molten material, magnetic stripes in the rock of the ocean floor, and the ages of the rocks themselves.
8 0
3 years ago
A quantity of a gas has an absolute pressure of 400 kPa and an absolute temperature of 110 degrees kelvin. When the temperature
KiRa [710]

Answer:

A) 854.46 kPa

Explanation:

P₁ = initial pressure of the gas = 400 kPa

P₂ = final pressure of the gas = ?

T₁ = initial temperature of the gas = 110 K

T₂ = final temperature of the gas = 235 K

Using the equation

\frac{P_{1}}{T_{1}}=\frac{P_{2}}{T_{2}}

Inserting the values

\frac{400}{110}=\frac{P_{2}}{235}

P₂ = 854.46 kPa

3 0
3 years ago
An object is placed 96.5 cm from a glass lens (n = 1.51) with one concave surface of radius 24 cm and one convex surface of radi
poizon [28]

Answer:

image is vertical at distance -203.62 cm

magnification is 2.110

Explanation:

given data

n = 1.51

distance u = 96.5 cm

concave radius r1 = 24 cm

convex radius r2 = 19.1 cm

to find out

final image distance and magnification

solution

we will apply here lens formula to find focal length f

1/f = n-1 ( 1/r1 - 1/r2)   .......................1

put here all value

1/f = 1.51 -1 ( -1/24 + 1/19.1)

f = 183.43

so from lens formula

1/f = 1/v + 1/u     .............................2

put here all value and find v

1/183.43 = 1/v + 1/96.5

so

v = −203.62 cm

so here image is vertical at distance -203.62 cm

and

magnification are = -v /u

magnification =  203.62 / 96.5

magnification is 2.110

3 0
4 years ago
Does an object which is positively charged contains all protons and no electrons?
Aleonysh [2.5K]

Answer:

Positively charged objects have electrons; they simply possess more protons than electrons.

Explanation:

2. An object that is electrically neutral contains only neutrons. Electrically neutral atoms simply possess the same number of electrons as protons.

<h3>Information:</h3>

If an atom has an equal number of protons and electrons, its net charge is 0. If it gains an extra electron, it becomes negatively charged and is known as an anion.

<h3>Tips:</h3>

If it loses an electron, it becomes positively charged and is known as a cation.

<h2>I hope this answers help you! :></h2>
7 0
3 years ago
Read 2 more answers
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