Answer:
12.5 ft/s
Explanation:
Height of person = 6 ft
height of lamp post = 10 ft
According to the question,
dx / dt = 5 ft/s
Let the rate of tip of the shadow moves away is dy/dt.
According to the diagram
10 / y = 6 / (y - x)
10 y - 10 x = 6 y
y = 2.5 x
Differentiate both sides with respect to t.
dy / dt = 2.5 dx / dt
dy / dt = 2.5 (5) = 12.5 ft /s
Answer:
1000m/s
Explanation:
velocity(v)=momentum(p)/mass
=100/.1
=1000m/s
Answer:
240 cm³
Explanation:
Weight = Buoyancy
mg = ρVg
m = ρV
(0.9 g/cm³ × 2400 cm³) = (1 g/cm³) V
V = 2160 cm³
The submerged volume is 2160 cm³, so the volume above the surface is 240 cm³.
Answer:
3234.2 W
Explanation:
Since intensity I = Power/Area. The intensity of the light from the sun, I = power radiated by sun/area of sphere of radius, r = 1.5 × 10¹¹ m.
So, I = 3.9 10²⁶W/4π(1.5 × 10¹¹ m)² = 2.069 × 10³ W/m².
Now, the power radiated on the patch of area 0.570 m² at the equator is
P = Icos27/A = 2.069 × 10³ W/m² cos27/0.570 m² = 1843.49/0.570 = 3234.2 W
Answer:
The final pressure will be 6.99 N/m^ 2
Explanation:
Initial volume of tire = 2.00 L
Initial pressure of the tire = 7.00 × 10 5 N/m 2
Initial temperature of tire 31 °C
P1V1 = P2V2
7.00 × 10 5 N/m 2 × V1 = 101325×100 → V1 = 1.45×10^(-5) m^3 = 1.45×10^(-2) L
Therefore new pressure = initial pressure - (pressure of released gas filling the entire 2 L)
pressure of released gas filling the entire 2 L = 2 L/(7.00 × 10^5 N/m^ 2 × 1.45×10^(-5) m^3) = 1.197 ×10^(-4) N/m^2
New pressure = 7.00 × 10^5 N/m^2 - 1.197 ×10^(-4) N/m^2
= 6.99 N/m^ 2
