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saw5 [17]
3 years ago
10

When a potential difference of 12 V is applied to a wire 6.7 m long and 0.31 mm in diameter the result is an electric current of

2.0 A . You may want to review (Pages 735 - 738) . Part A What is the resistivity of the wire
Physics
1 answer:
anastassius [24]3 years ago
7 0
The wire needs to be sauderwired to be connected back into place to get energy into column so it came function properly again!
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How do its eight arms help an octopus obtain food
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The more arms it has the less of a chance the prey has to swim away.
5 0
3 years ago
The position of a charge in an electric field gives it _____electric
kykrilka [37]

Answer:

The space surrounding a charged object is affected by the presence of the charge; an electric field is established in that space. A charged object creates an electric field - an alteration of the space or field in the region that surrounds it. Other charges in that field would feel the unusual alteration of the space.

Explanation:

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3 years ago
Question 7 of 25
tiny-mole [99]

Answer:

2PBr₃ + 3Cl₂ → 2PCl₃ + 3Br₂

2Na + MgCl₂ → 2NaCl + Mg

Explanation:

A balanced chemical equation is a chemical equation that have an equal number of elements of each type on both sides of the equation

Among the given chemical reactions, we have;

2PBr₃ + 3Cl₂ → 2PCl₃ + 3Br₂

In the above reaction;

The number of phosphorus, P, on either side of the equation = 2

The number of bromine atoms, Br, on either side of the equation = 6

The number of chlorine atoms, Cl, on either side of the equation = 6

Therefore, the number of elements in the reactant side and products side of the reaction are equal and the reaction is balanced

The second balanced chemical reaction is 2Na + MgCl₂ → 2NaCl + Mg

In the above reaction, there are two sodium atoms, Na,  one magnesium atom and two chlorine atoms on both sides of the reaction, therefore, the reaction is balanced

6 0
3 years ago
A 7.5 cm object is 14 cm from a concave lens, which has a focal length of –7 cm. Its image is 5 cm in front of the lens. What is
Rama09 [41]
Given conditions:
height of object = 7.5cmdistance of object from mirror  = 14 cmfocus length = -7 cmimage distance =  ?
Using mirror formula: 
1/(focus length) = 1/(object distance) + 1/(image distance)
or, -1/7 = 1/14 + 1/(image distance)
or, image distance = -4.66cm (the image formed is a virtual image)


Also, magnification of image is:
image height /height of object = - image distance /object distance
or, image height = - image distance / object distance * height of object
or, image height = -(-4.66) / 14 * 7.5 = 2.49 = 3(nearest whole number)
3 0
3 years ago
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Which statements describe properties of stars?
Ede4ka [16]

Statements 1, 3, and 5 are true.

(A, C, and E)

7 0
3 years ago
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