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Vera_Pavlovna [14]
3 years ago
13

Evelyn and Tia are having a bake sale. They have 453 cookies. Each box holds 12 cookies. How many boxes do they need?

Mathematics
1 answer:
balu736 [363]3 years ago
4 0

Answer:

38 boxes

Step-by-step explanation:

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Liono4ka [1.6K]

Answer:

P = mgh

P/mg = h

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Hope this helps!! :)

Step-by-step explanation:

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If a/b &lt; c/d with b &gt; 0, d &gt; 0, prove that a+c / b+d lies between the two fractions a/b and c/d .​
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Divide through everything by <em>b</em> :

\dfrac{a+c}{b+d} = \dfrac{\dfrac ab + \dfrac cb}{1 + \dfrac db}

Since <em>a/b</em> < <em>c/d</em>, it follows that

\dfrac{a+c}{b+d} < \dfrac{\dfrac cd+\dfrac cb}{1 + \dfrac db}

Multiply through everything on the right side by <em>b/d</em> to get

\dfrac{a+c}{b+d} < \dfrac{\dfrac{bc}{d^2}+\dfrac cd}{\dfrac bd+1} = \dfrac{\dfrac cd\left(\dfrac bd+1\right)}{\dfrac bd+1} = \dfrac cd

and so (<em>a</em> + <em>c</em>)/(<em>b</em> + <em>d</em>) < <em>c/d</em>.

For the other side, you can do something similar and divide through everything by <em>d</em> :

\dfrac{a+c}{b+d} = \dfrac{\dfrac ad + \dfrac cd}{\dfrac bd + 1}

and <em>a/b</em> < <em>c/d</em> tells us that

\dfrac{a+c}{b+d} > \dfrac{\dfrac ad + \dfrac ab}{\dfrac bd + 1}

Then

\dfrac{a+c}{b+d} > \dfrac{\dfrac ab + \dfrac{ad}{b^2}}{1 + \dfrac db} = \dfrac{\dfrac ab\left(1+\dfrac db\right)}{1 + \dfrac db} = \dfrac ab

and so (<em>a</em> + <em>c</em>)/(<em>b</em> + <em>d</em>) > <em>a/b</em>.

Then together we get the desired inequality.

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3 years ago
What is the domain for the function below?<br> Х 1 3 5 7 Y 2 4 6 8
erma4kov [3.2K]
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Step-by-step explanation:

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