Answer:
Step-by-step explanation:
These come directly from my textbook, so I'm not sure if your teacher will accept this kind of work.
1. Angle construction:
Given an angle. construct an angle congruent to the given angle.
Given: Angle ABC
Construct: An angle congruent to angle ABC
Procedure:
1. Draw a ray. Label it ray RY.
2. Using B as center and any radius, draw an arc that intersects ray BA and ray BC. Label the points of intersection D and E, respectively.
3. Using R as center and the same radius as in Step 2, draw an arc intersecting ray RY. Label the arc XS, with S being the point where the arc intersects ray RY.
4. Using S as center and a radius equal to DE, draw an arc that intersects arc XS at a point Q.
5. Draw ray RQ.
Justification (for congruence): If you draw line segment DE and line segment QS, triangle DBE is congruent to triangle QRS (SSS postulate) Then angle QRS is congruent to angle ABC.
You can probably also Google videos if it's hard to imagine this. Sorry, construction is super hard to describe.
The probability would be 0.9738.
We first find the z-score for each end of this interval:
z = (x-μ)/(σ/√n) = (100-110)/(18/√49) = -10/(18/7) = -3.89
z = (x-μ)/(σ/√n) = (115-110)/(18/√49) = 5/(18/7) = 1.94
Using a z-table (http://www.z-table.com) we see that the probability that a score is less than the first z-score is 0. The probability under the curve to the left of, less than, the second z-score is 0.9738. Subtracting these we find the area between them:
0.9738 - 0 = 0.9738.
Answer:
(4c-1)(y+3)
Step-by-step explanation:
4c(y+3) -(y+3)
=(4c-1)(y+3)
Answer:
Part 1) The lateral area of the cone is 
Part 2) The lateral surface area of the cylinder is 
Part 3) The surface area of the crayon is 
Step-by-step explanation:
Part 1) Find the lateral area of the cone
The lateral area of the cone is equal to
we have
substitute
Part 2) Find the lateral surface area of the cylinder
The lateral area of the cylinder is equal to
we have
substitute
Part 3) Find the surface area of the crayon
The surface area of the crayon is equal to the lateral area of the cone, plus the lateral area of the cylinder, plus the top area of the cylinder plus the bottom base of the crayon
<em>Find the area of the bottom base of the crayon</em>
![A=\pi[r2^{2}-r1^{2}]](https://tex.z-dn.net/?f=A%3D%5Cpi%5Br2%5E%7B2%7D-r1%5E%7B2%7D%5D)
where
r2 is the radius of the cylinder
r1 is the radius of the cone
substitute
![A=\pi[1.5^{2}-1^{2}]](https://tex.z-dn.net/?f=A%3D%5Cpi%5B1.5%5E%7B2%7D-1%5E%7B2%7D%5D)
<em>Find the area of the top base of the cylinder</em>
<em>Find the surface area</em>
Answer:
The revenue depends on the number of people n that purchases tickets, knowing that each ticket costs $30.00, the total revenue will be:
f(n) = $30.00*n
Now, we also know that the stadium is capable of seating a maximum of m fans, so the maximum possible value for n is m.
Now, for the function f(n), we have that:
The domain is the set of the possible values of n
The range is the set of the possible values of f(n).
We want to find the domain.
First, the minimum possible value of n is 0, the case where nobody purchases a ticket.
The maximum possible value of n is m, this is the case where the stadium is full.
Then the domain will be:
D= {n,m ∈ Z, 0 ≤ n ≤ m}
Where we imposed that n must be an integer number because n represents a whole quantity.
