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defon
3 years ago
10

How do you solve this ratio table?

Mathematics
1 answer:
viva [34]3 years ago
6 0
What Ratio table???  There is no pic
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How do i solve this using imaginary numbers? PLEASE HELP
Tasya [4]

Answer:

14 -2i

Step-by-step explanation:

9 + sqrt(-4) - ( -5 + sqrt(-16))

We know the sqrt of a negative number is i * sqrt(number)

9 + isqrt(4) - ( -5 + isqrt(16))

9 + 2i - (-5 + 4i)

Distribute the negative sign

9+2i +5 -4i

Combine like terms

14 -2i

8 0
3 years ago
What is the relationship between the angles?<br> Another answer is none of the above.
Oduvanchick [21]
Answer none of the above
Reason - they are adjacent angles
Not vertical
Not complementary
Not supplementary
7 0
2 years ago
Read 2 more answers
Blake has a glass tank. First, he wants to put some marbles in it, all of the same volume. Then, he wants to fill the tank with
NeTakaya

Answer:

32 liters is the volume of the glass tank

3 0
2 years ago
Please help! / 50 points
lutik1710 [3]

Answer:

Solution given:

radius [r]=4

height [h]=5

we have

Surface area of cylinder=2πr(r+h)

=2π×4(4+5)

=<u>72πunits³ is a required volume.</u>

3 0
3 years ago
Advertisements for the Sylph Physical Fitness Center claim that completion of their course will result in a loss of weight (meas
MrMuchimi

Answer:

90% confidence interval for the mean weight loss for the population represented by this sample assuming that the differences are coming from a normally distributed population is [1.989 ,13.5105]

Step-by-step explanation:

The data given is

                        Mean                 Std Dev

Before            177.25                29.325

After              169.50                    22.431

Difference        7.75                    8.598

Hence d`=   7.75 and sd=   8.598

The 90% confidence interval for the difference in means for the paired observation is given by

d` ± t∝/2(n-1) *sd/√n

Here  t∝/2(n-1)=1.895  where n-1= 8-1= 7 d.f

and  ∝/2= 0.1/2=0.05

Putting the values

d` ± t∝/2(n-1) *sd/√n

7.75  ±1.895 *  8.598 /√8

 7.75  ± 5.7605

1.989 ,13.5105

90% confidence interval for the mean weight loss for the population represented by this sample assuming that the differences are coming from a normally distributed population is [1.989 ,13.5105]

3 0
3 years ago
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