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Sliva [168]
4 years ago
7

Find the distance between J (-5,-3) and K (1,5)

Mathematics
1 answer:
allsm [11]4 years ago
5 0

Answer:

10

Step-by-step explanation:

^1÷2 equals square root i can not put a square root sing since i am typing.

1. Start with the distance formula between 2 points which is the: ((y"- y')^2+(x" -x')^2))^1÷2

2. plug in the cordinates for (-5,-3) and (1,5)

with (x'= -5, y'= -3) and (x"= 1, y"= 5 )

3. know that you know that we have

d= ((5+3)^2)+(1+5)^2))^(1÷2)

4 this gives us ((8^2)+(6^2))^(1÷2)

5 know 8^2=64 and 6^2=36 eqaling to 64+36=100

6. know the (100)^(1÷2) = 10

7. so the distance between j and k is 10

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3 0
3 years ago
Confused on this part
Andre45 [30]

Answer:

The first 2 and the last one

Step-by-step explanation:

You need to have an input per output, and to choose one or multiple the need to have a continuous pattern. Ex.+5 ad -2 on both sides every time would be a linear function.  

6 0
3 years ago
Here's an easy question for points: 5 x 2/6 =
Allushta [10]
5 times 2/6 is 10/6
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6 0
3 years ago
Read 2 more answers
#8 please. GCF of 117, 99, and 126
Advocard [28]
The factors of 117 are: 1, 3, 9, 13, 39, and 117
The factors of 99 are: 1, 3, 9, 11, 33, and 99 
The factors of 126 are: 1, 2, 3, 6, 7, 9, 14, 18, 21, 42, 63, and 126

The greatest common factors of 117, 99, and 126 are: 1, 3, and 9. And according to your answer choices your answer is C. 9
7 0
3 years ago
I solved this answer already and I got 43, but I don’t know if it’s correct so
faltersainse [42]

Answer:

= 43

Step-by-step explanation:

{7 × 2^{3} - 7} -2 ×3

Solve the brackets first

{7 × 8 - 7}  -2 ×3

{56 - 7}  -2 ×3

49  -2 ×3

49 -6

= 43

you are right

8 0
3 years ago
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