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2 years ago

Taking over a family business can help to maintain the goodwill of the customers.

Business

2 answers:

romanna [79]2 years ago

4 0

Answer:

The answer is: true

Explanation:

Customers' goodwill can be defined as the relationship that develops between the customers and a business. Obviously this relationship is based on the products or services that the business sells, and many times it can become an intangible asset.

For example, no one is going to develop customer goodwill when purchasing on the internet. But some businesses create a special relationship with their clients, like a local bakery or coffee shop. When those types of family business is passed on to a son or daughter, the relationship with the customers will remain.

daser333 [38]2 years ago

3 0

Answer:

it is trueeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeee

Explanation:

trust myself g

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3 years ago

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When individuals acquire, process, and act on relevant economic information promptly in their own self-interest and investigate

notsponge [240]

Answer: rational

Explanation:

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3 years ago

An American executive is going on a business trip to Japan and England. Before she departs, she purchases $10,000 worth of Japan

Sedbober [7]

Answer:

The correct answer is $907.76.

Explanation:

According to the scenario, computation of the given data are as follow:-

1¥ = 82.54$

1£ = 132.03¥

Convert pounds to us dollars= £ ÷ $ = £132.03 ÷ $82.54

= 1.60$ ÷ £

Mean, 1£ = 1.6$

She has £567.35 .

After converting the pound into the dollar, she will receive = £567.35 × $1.60

= $907.76

Hence, she receive $907.76 if she sells the pounds.

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2 years ago

A card from a 52 card deck is lost. We then draw 2 cards from the 51 remaining cards. What is the probability they are both diam

Nonamiya [84]

Answer:

$\frac{1}{17}$

Explanation:

Let D be the event that the lost card is a diamond

and D' be the event that the lost card is a non diamond

Therefore,

P(D) = $\frac{13}{52}$ = 0.25

P(D') = $\frac{39}{52}$ = 0.75

Now,

Event that the cards picked up are both diamonds = A

Thus,

P( A | D) = $\frac{12}{51 }\times\frac{11}{50}$ [ As One Diamond Card is lost ]

And,

P(A | D') = $\frac{13}{51}\times\frac{12}{50}$ [ As One Non-Diamond card is lost ]

Therefore,

P(A) = P(D) × P(A | D) + P(D') × P( A | D')

= 0.25 × $\frac{12}{51 }\times\frac{11}{50}$ + 0.75 × $\frac{13}{51}\times\frac{12}{50}$

= $\frac{1}{17}$

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2 years ago

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Brilliant_brown [7]

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2 years ago

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