The number of unique ways is given by the number of possible
combination having distinct members.
The number of unique ways there are to arrange 4 of the 6 swimmers are <u>15 ways</u>.
Reasons:
The given parameters are;
The number of swimmers available = 6 swimmers
The number of swimmers the coach must select = 4 swimmers
Required:
The number of unique ways to arrange 4 of the 6 swimmers.
Solution:
The number of possible combination of swimmers is given as follows;
Therefore, the coach can select 4 of the 6 available swimmers in <u>15 unique ways</u>
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Answer:
3×
Step-by-step explanation:
0.00000003
Move the decimal so there is one non-zero digit to the left of the decimal point. The number of decimal places you move will be the exponent on the
10
. If the decimal is being moved to the right, the exponent will be negative. If the decimal is being moved to the left, the exponent will be positive.
Step-by-step explanation:
x-the initial number of coconuts
x=3y+1
2y=3z+1
2z=3×7+1=>z=11=>y=17=>x=52
The Pythagorean theorem can be used for this.
.. (tip distance)² = (shadow length)² + (tree height)²
.. tree height = √((tip distance)² -(shadow length)²)
.. tree height = √((60 ft)² -(40 ft)²) = √(2000 ft²)
.. tree height ≈ 44.72 ft
Answer:
Step-by-step explanation:
Let the side of the square base be x
h be the height of the box
Volume V = x²h
13500 = x²h
h = 13500/x² ..... 1
Surface area = x² + 2xh + 2xh
Surface area S = x² + 4xh ...... 2
Substitute 1 into 2;
From 2; S = x² + 4xh
S = x² + 4x(13500/x²)
S = x² + 54000/x
To minimize the amount of material used; dS/dx = 0
dS/dx = 2x - 54000/x²
0 = 2x - 54000/x²
0 = 2x³ - 54000
2x³ = 54000
x³ = 27000
x = ∛27000
x = 30cm
Since V = x²h
13500 = 30²h
h = 13500/900
h = 15cm
Hence the dimensions of the box that minimize the amount of material used is 30cm by 30cm by 15cm
