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Basile [38]
3 years ago
11

Look at the given spectroscopy data. How many degrees of unsaturation are present in this molecule? The IR at 1735 cm-1 is indic

ative of a type bond and when combined with the 13C NMR signal at 172 ppm and general H NMR is indicative of a(n) functional group. The 1HNMR peak at 6.3 ppm and broad signal at 3325 cm-1 in the IR is indicative of a(n) that is bonded to a
Physics
1 answer:
Finger [1]3 years ago
6 0

Answer:

Explanation:

Degree of unsaturation can be calculated by the formula

DU = (2C+2+N-X-H)/ 2 where

C is the number of carbons

N is the number of nitrogens

X is the number of halogens (F, Cl, Br, I)

H is the number of hydrogens. Oxygen and sulfur are not included in the formula because saturation is unaffected by these elements

So for C18H29NO2

DU = (36+2+1-29)/ 2 = 05.

The IR at 1735 cm-1 is indicative of a carbonyl type bond and when combined with the 13C NMR signal at 12 ppm and general H NMR is indicative of a (n) ester funtional group.

The HNMR peak at 6.3 ppm and broad signal at 3325 cm-1 in the IR is indicative of a (n) amine that is bonded to sp2 hybridized central atom.

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At the time of quark confinement, when the universe was 10-6 seconds old, there is found to be one additional proton for every billion antiprotons.

<h3>What is quark confinement?</h3>

Note that  one quark is never found on its own but if particles are said to be smashed together and quarks are found, they are said to be like ends of rubber bands that expands.

Hence, At the time of quark confinement, when the universe was 10-6 seconds old, there is found to be one additional proton for every billion antiprotons.

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7 0
2 years ago
A bowling ball of mass 5.8 kg moves in a
evablogger [386]

Answer:

Velocity of the ping pong ball must be = V2= 6,035.34m/s

Explanation:

M1= momentum of the bowling ball

m1 = mass of the bowling ball= 5.8kg

v1= velocity of the bowling ball= 1.59m/s

M2= momentum of the ping pong ball

m2= mass of the ping pong ball= 1.528 g/1000=  0.001528kg

v2= velocity of the ping pong ball

Momentum of the bowling ball= M1= m1v1= 5.8* 1.59= 9.222 kg-m/s

Momentum of the ping pong ball = M2= M1= m2v2

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4 years ago
A Navy vessel is traveling due north during wartime. A torpedo has been launched by an enemy directly toward the stern (rear) of
Anika [276]

Answer:

The correct option is;

B) No, the Navy vessel is slower

Explanation:

The speed of some torpedoes can be as high as 370 km/h. The average speed of a fast Navy vessel is approximately 110 km/h

Therefore, the torpedoes travel approximately 3 times as fast as the (slower) Navy vessel, such that the torpedo covers three times the distance of the Navy vessel in the same time and therefore, if the Navy vessel and the torpedo continue in a straight line (in the same direction) due north the vessel can not outrun the torpedo

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3 years ago
I really need help please just answer at least one
yuradex [85]

Answer:

9) a = 25 [m/s^2], t = 4 [s]

10) a = 0.0875 [m/s^2], t = 34.3 [s]

11) t = 32 [s]

Explanation:

To solve this problem we must use kinematics equations. In this way we have:

9)

a)

v_{f}^{2} = v_{i}^{2}-(2*a*x)\\

where:

Vf = final velocity = 0

Vi = initial velocity = 100 [m/s]

a = acceleration [m/s^2]

x = distance = 200 [m]

Note: the final speed is zero, as the car stops completely when it stops. The negative sign of the equation means that the car loses speed or slows down as it stops.

0 = (100)^2 - (2*a*200)

a = 25 [m/s^2]

b)

Now using the following equation:

v_{f} =v_{i} - (a*t)

0 = 100 - (25*t)

t = 4 [s]

10)

a)

To solve this problem we must use kinematics equations. In this way we have:

v_{f} ^{2} =  v_{i} ^{2} + 2*a*(x-x_{o})

Note:  The positive sign of the equation means that the car increases his speed.

5^2 = 2^2 + 2*a*(125 - 5)

25 - 4 = 2*a* (120)

a = 0.0875 [m/s^2]

b)

Now using the following equation:

v_{f}= v_{i}+a*t\\

5 = 2 + 0.0875*t

3 = 0.0875*t

t = 34.3 [s]

11)

To solve this problem we must use kinematics equations. In this way we have:

v_{f} ^{2} =  v_{i} ^{2} + 2*a*(x-x_{o})

10^2 = 2^2 + 2*a*(200 - 10)

100 - 4 = 2*a* (190)

a = 0.25 [m/s^2]

Now using the following equation:

v_{f}= v_{i}+a*t\\

10 = 2 + 0.25*t

8 = 0.25*t

t = 32 [s]

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Answer: Negatively charged particles are repelled by other negatively charged particles

Explanation:

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