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disa [49]
3 years ago
11

A student drove to the university from her home and noted that the odometer reading of her car increased by 17.9 km. The trip to

ok 26.6 min.
a) What was her average speed, in kilometers per hour?
b) IS she returned home by the same path 7 h 30 min after she left, what was her average speed and velocity for the entire trip?
Physics
1 answer:
Zielflug [23.3K]3 years ago
5 0

Answer:

See calculation below

Explanation:

Average speed = Distance/Time

a) Given

Distance = 17.9km

Time = 26.6minutes

Time = 26.6/60 hr

Time = 0.443hr

Average speed  = 17.9/0.443

Average speed = 40.38km/hr

b) If she returned home by the same path 7 h 30 min after she left, the distance will be the same;

Distance = 17.9km

Time = 7.5hr

Average speed = 17.9/7.5

Average speed = 2.387km/hr

Velocity of the entire trip = 40.38km/hr + 2.387km/hr

Velocity of the entire trip = 42.77km/hr

<em>Hence the velocity of the entire trip is 42.77km/hr</em>

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