Question

Paul's mom sent him to the grocery store with $10 to buy bread and cheese for sandwiches. Paul picked out a loaf of bread that costs $3.25, and a deli cheese that costs $5.99 a pound. He would like to buy as much cheese as possible, so he asks the deli worker to see how much each slice weighs. Each slice weighs 0.04 pounds. Which inequality can be solved to find x, the number of slices that Paul can afford to buy?

Answer 1

Given:

Total amount = $10

Cost of loaf of bread = $3.25

Cost of cheese = $5.99 per pound

Each slice weights = 0.04 pounds.

To find:

The inequality for the number of slices that Paul can afford to buy.

Solution:

Let x be the number of slices that Paul can afford to buy.

Weight of on slice is 0.04 pounds. So, weight of x slices is 0.04x pound.

Cost of cheese = $5.99 per pound

So, total cost of cheese for x slices = $5.99 × 0.04x

Now, Paul has $10 to buy bread and cheese for sandwiches. Cost of loaf of bread is $3.25.

$3.25+(5.99\times 0.04x)\leq 10$

$0.2396x\leq 10-3.25$

$0.2396x\leq 6.75$

Divide both sides by 0.2396.

$x\leq \dfrac{6.75}{0.2396}$

$x\leq 28.172$

The maximum integer value of x is 28.

Therefore, the required inequity is $3.25+(5.99\times 0.04x)\leq 10$ and 28 number of slices Paul can afford to buy.