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Andru [333]
3 years ago
13

Sarah and Gavyn win some money and share it in the ratio 5:3. Sarah gets £26 more than Gavyn. How much did Gavyn get?

Mathematics
1 answer:
maks197457 [2]3 years ago
4 0

Answer:

£39

Step-by-step explanation:

Let Gavyn's share = x

Since, Sarah gets £26 more than Gavyn.

Sarah's Share = x+26

Equating the Ratio of their Shares and the actual sum received

x+26 : x = 5:3

Converting to Fractions

\dfrac{x+26}{x}=\dfrac{5}{3}

Cross multiply

5x=3(x+26)

5x=3x+78

5x-3x=78

2x=78

Divide both sides by 2

x=39

Therefore: Gavyn's share x = £39

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There are 80 pupils in a school. If 32 are boys, what percentage are boys?
maks197457 [2]

Answer:

40%

Step-by-step explanation:

32/80=.4

8 0
3 years ago
Read 2 more answers
The grid shows Figure Q and its image Figure Q′ after a transformation.
Svetach [21]

The transformation of pentagon Q to pentagon Q' is a clockwise rotation of 180° about the origin.

<h3>What is transformation?</h3>

A transformation is a general term for four specific ways to manipulate the shape or position of a point, a line, or a geometric figure.

We have,

Coordinates of a pentagon Q.

(2, 4), (3, 7), (7, 5), (5,4), and (4,2).

Coordinates of pentagon Q'.

(-2, -4), (-3, -7), (-7, -5), (-5,-4), and (-4,-2).

We see that the coordinates of each point of the pentagon Q have changed their position as negative coordinates in pentagon Q'

The coordinates of pentagon Q are in (x, y) which can be assumed to be in the first quadrant of the coordinate plane.

The coordinates of pentagon Q' are in (-x, -y) which is in the 3rd quadrant.

From the first quadrant to 3rd quadrant there is a rotation of 180°.

Thus the transformation of pentagon Q to pentagon Q' is a clockwise rotation of 180° about the origin.

Learn more about transformation here:

brainly.com/question/4458799

#SPJ1

8 0
1 year ago
A calculus exam has a mean of µ = 73 and a standard deviation of σ = 4. Trina's score on the exam was 79, giving her a z-score o
kirza4 [7]

Answer:

I get z = +1.8

x= 79

m= 73;s= 4;z= (x-m)/s= 1.5

hope it helps you

7 0
4 years ago
Help please it is due today
Svet_ta [14]

Answer:

Jane's situation is the one which represents a porportional relationship.

Step-by-step explanation:

To verify the proportionality betwen a ratio you have to divide all the ratios and all them have to get the same constant factor.

So, if you divide the matt's ratios you aren't gonna find the same constant factor

12/1=12

20/2=10

31/2=15,5

But if you try with Jane's ones:

12/1=12

24/2=12

36/3=12

This 12 is the known constant factor, which show us that these ratios are proportional.

8 0
3 years ago
What is the height of the triangle? 12 units 24 units 36 units 72 units.
konstantin123 [22]

Height of the triangle is the altitude of the triangle and which is drawn perpendicular from the vertex of the triangle to the opposite side. The height of the tringle is 24 units. Hence option 2 is the correct option.

<h3>Given information-</h3>

The triangle for the given problem is shown in the image below.

Form the figure the length of the each side is 16 \sqrt{3} units.

As all the sides are equal thus the \Delta MNO is a equilateral triangle in which the height of the divides the triangle into two equal part of the length 8\sqrt{3} at point <em>R.</em>

<h3>Height of the triangle-</h3>

Height of the triangle is the altitude of the triangle and which is drawn perpendicular from the vertex of the triangle to the opposite side.

Now in the  \Delta MRN, the length of the hypotenuse is 16 \sqrt{3} units and the length of the base is 8\sqrt{3} units. Let <em>h </em>is the height of the triangle thus by the Pythagoras theorem,

(16\sqrt{3})^2 =(8\sqrt{3})^2+h^2

Solve for <em>h,</em>

<em />

<em />\begin{aligned}h^2 &=(16\sqrt{3})^2 -(8\sqrt{3})^2\\h^2 &=16\times16\times3 -8\times8\times3\\h^2 &=576\\h &=\sqrt{576}\\h &=24\\\end<em />

<em />

Thus the height of the tringle is 24 units. Hence option 2 is the correct option.

Learn more about the equilateral triangle here;

brainly.com/question/4268382

5 0
2 years ago
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