So if you want to add
we distribute
a(b+c)=ab+ac so
-2(m+n-4)=-2m-2n+8
5(-2m+2n)=-10m+10n
n(m+4n-5)=mn+4n^2-5n
so total we ahve
-2m-2n+8-10m+10n+mn+4n^2-5n
group like terms
4n^2+-2m-10m-2n+10n-5n+mn+8
add like temrs
4n^2-12m+3n+mn+8
Using the left or right side of triangle, you can conclude that the midsegment will divide the triangle in both midlines of the sides. This means the length of the line would be half of the line below it. The equation would be:
47/4x+2= 94/ 4x+44
4x+44/ 4x+2 = 94/47
4x+ 44 / 4x+2 =2
4x+44 = 2(4x+2)
4x+44 = 8x+4
4x-8x= 4-44
-4x= -40
x= 10
Then the length of midline would be:
4x+2= 4(10)+2= 42
Divide by each number below it and find that each does not come out to a whole number except for dividing by 1
