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stellarik [79]
3 years ago
13

Solve for b. b +3(3 - 2b) = 1 - 2(b + 1)

Mathematics
1 answer:
Vika [28.1K]3 years ago
7 0

Answer:

b+3(3-2b)=1-2(b+1)  

One solution was found :

                  b = 10/3 = 3.333

Rearrange:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

               b+3*(3-2*b)-(1-2*(b+1))=0  

Step by step solution :

Step  1  :

Equation at the end of step  1  :

 (b+(3•(3-2b)))-(1-2•(b+1))  = 0  

Step  2  :

Equation at the end of step  2  :

 (b +  3 • (3 - 2b)) -  (-2b - 1)  = 0  

Step  3  :

Equation at the end of step  3  :

 10 - 3b  = 0  

Step  4  :

Solving a Single Variable Equation :

4.1      Solve  :    -3b+10 = 0  

Subtract  10  from both sides of the equation :  

                     -3b = -10

Multiply both sides of the equation by (-1) :  3b = 10

Divide both sides of the equation by 3:

                    b = 10/3 = 3.333

One solution was found :

                  b = 10/3 = 3.333

Step-by-step explanation:

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