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mixer [17]
2 years ago
6

NEED HELP ASAP PLS DUE TODAY !!!

Mathematics
1 answer:
S_A_V [24]2 years ago
6 0

Answer:

with what do you need help? if you took a picture i cant see it at all

Step-by-step explanation:

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Let f(x) = 4x - 5 and g(x) = 6x - 3. Find f(x) - g(x).
professor190 [17]
F(X) = 4x - 5
G(X) = 6x - 3

F(x) - G(x)

(4x - 5) - (6x - 3)

4x - 5 - 6x + 3

-2x - 2

-2(X + 1).

I believe this would be the simplified solution.
3 0
3 years ago
Read 2 more answers
Which statement about this figure is true?
kirza4 [7]

Answer:

there is no attached image

Step-by-step explanation:

3 0
2 years ago
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Can you explain how a table can be used to find the rate of change
serg [7]

A table will generally give you an output value for each of several input values. To find the average rate of change over some range of inputs, divide the difference between output values by the difference between input values for the corresponding inputs.

For example, consider the table

input .... output

.. 1 ............ 3

.. 3 ........... -5

The average rate of change between these input values is

... (change in output)/(change in input) = (-5 -3)/(3 - 1) = -8/2 = -4.

6 0
3 years ago
The product of two numbers is 41. One of the numbers
shepuryov [24]
<h3>Answer:   5 - 4i     (choice A)</h3>

===================================================

Work Shown:

x = the other number

(5+4i)*x = 41

x = 41/(5+4i)

x = 41*(5-4i)/( (5+4i)*(5-4i) ) ..... see note below

x = 41*(5-4i)/( 41 )

x = (41/41)*(5-4i)

x = 5 - 4i  

As a way to check, (5+4i)*(5-4i) = 5^2+4^2 = 25+16 = 41

The rule used is (a-bi)(a+bi) = a^2 + b^2

-----------

Note:  I multiplied top and bottom by (5-4i) to get rid of the imaginary term in the denominator.

3 0
2 years ago
Which equation could represent a circle with a center located at (11,-5)
Anon25 [30]
The standard equation of a circle is:

(x-h)^2-(y-k)^2=r^2 where (h,k) is the center and r is the radius.

We need to make an equation of a circle, whose center is (11,-5) with any radius. Therefore, substitute the value.


(x-h)^2-(y-k)^2=r^2 \\ (11,-5)=(h,k) \\ (x-11)^2-(y-5)^2=64

The bolded part is your answer. Since the radius is not given, we can put any value.

6 0
3 years ago
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