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azamat
4 years ago
11

Using the quadratic formula to solve 11x2 – 4x = 1, what are the values of x?

Mathematics
2 answers:
Ann [662]4 years ago
8 0

Answer:

Given the quadratic equation: 11x^2- 4x = 1

we can write this equation as;

11x^2-4x-1 = 0                   ......[1]

A quadratic equation is in the form of ax^2+bx+c =0 where a, b , c are coefficient and

the solution for this equation is given by;

x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}   where a≠0

On comparing the above formula with an equation [1] we have;    

a = 11 , b = -4  and  c =-1

Substitute these given values to solve for x;

x = \frac{-(-4)\pm\sqrt{(-4)^2-4(11)(-1)}}{2(11)}

x = \frac{ 4\pm\sqrt{16+44}}{22}

x = \frac{ 4\pm\sqrt{60}}{22}

or

x = \frac{ 4\pm 2\sqrt{15}}{22}

x = \frac{ 2\pm \sqrt{15}}{11}

Simplify:

x= \frac{2 + \sqrt{15} }{11} and x= \frac{2 - \sqrt{15} }{11}

Therefore, the values of x are;

x= \frac{2 + \sqrt{15} }{11} , \frac{2 - \sqrt{15} }{11}


Neporo4naja [7]4 years ago
4 0
\frac{2}{11} +/-   \frac{ \sqrt{15} }{11}
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