Answer:
a) The interval for those who want to go out earlier is between 43.008 and 46.592
b) The interval for those who want to go out later is between 47.9232 and 51.9168
Step-by-step explanation:
Given that:
Sample size (n) =128,
Margin of error (e) = ±4% =
a) The probability of those who wanted to get out earlier (p) = 35% = 0.35
The mean of the distribution (μ) = np = 128 * 0.35 = 44.8
The margin of error = ± 4% of 448 = 0.04 × 44.8 = ± 1.792
The interval = μ ± e = 44.8 ± 1.792 = (43.008, 46.592)
b) The probability of those who wanted to start school get out later (p) = 39% = 0.39
The mean of the distribution (μ) = np = 128 * 0.39 = 49.92
The margin of error = ± 4% of 448 = 0.04 × 49.92 = ± 1.9968
The interval = μ ± e = 44.8 ± 1.792 = (47.9232, 51.9168)
The way for those who want to go out earlier to win if the vote is counted is if those who do not have any opinion vote that they want to go earlier
Answer:
7.5 miles per hour.
Step-by-step explanation:
We have been given that Mr. Ward runs a lot. He ran 45 minutes each day, 5 days each week, for 16 weeks.
First of all, we will find time for that Mr. Ward ran in 16 weeks.
We will multiply 5 by 16 to find number of days for that Mr. Ward ran and then we will multiply the result by 45 minutes to find the time.
Now, we will divide 3600 minutes by 60 minutes to convert time into hours as:
Now, we will divide 450 miles by 60 hours to find Mr. Ward's average speed as:
Therefore, Mr. Ward's average speed in 7.5 miles per hour.
Y=1/5x-2
Hope this helped :)
x=1
Is dat what u want? If not tell me and I'll help u
Hope this helped :)
STEP 1:
Total runners originally= 8
# of runners to receive trophies= 4
8-2 drop outs= 6 runners total now
STEP 2:
= # of trophies ÷ total runners now
= 4/6
simplify by 2
= (4÷2)/(6÷2)
= 2/3 runners
ANSWER: 2/3 of the remaining runners will win a trophy.
Hope this helps! :)
