To solve for AC in the given inscribed angle we proceed as follows:
An inscribed angle is an angle with its vertex "on" the circle formed by two intersecting chords as in our drawing. Thus here we shall use the formula:
Inscribed Angle=1/2 intercepted Arc
thus
m∠ABC=1/2mAC
thus plugging in our values we shall have:
4x-3.5=1/2(4x+17)
4x-3.5=2x+8.5
solving simplifying and solving for x we obtain
4x-2x=8.5+3.5
2x=12
hence
x=12/2
x=6°
Answer:
They are any number in front of a variable so like 4x 7y or 8z. 4, 7 and 8 are the coefficients. A number by itself is a constant. For example 3, 1 and 9 are constants.
I don’t know what I’m solving for so I solved for h and with that it should be h=q/2+m/2
Explanation:
15h-m=13h+q
-13h -13h
———————-
2h-m=q
+m +m
———————-
2h=q+m
/2 /2 /2
———————-
H=q/2+m/2