All categories

2 years ago

Explain how the value of the 7 in 327,902 will charge if you move it to the tens place

2 answers:

5 0

It will change because you will move it back, so instead of being in the thousands place, (being 7,000) it will be in the tens place. (being 70)

oee [108]2 years ago

5 0

The 7 is currently in the thousands place, so the number currently reads three hundred twenty- seven thousand, nine hundred two.
If you move the seven to the tens place the number becomes smaller and then reads three hundred twenty thousand, nine hundred seventy- two.
You lost seven thousand from the first option, but yet gained seventy in the second option.

You might be interested in

What is the value of y?

Gelneren [198K]

Answer:

try 70

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

297-325 over 297<br> how can i turn that fraction into a percentage?

Rainbow [258]

Answer:

Step-by-step explanation:

by moving the decimal 2 times to the right

5 0

2 years ago

Convert the complex number z = 4 - 10i from rectangular form to polar form.

mrs_skeptik [129]

ANSWER

$r = 2 \sqrt{29} ( \cos(292 \degree) + \sin(292 \degree))$

EXPLANATION

The polar form of a complex number ,

$z = x + yi$

is given by:

$z = r( \cos( \theta) + i \sin( \theta) )$

where

$r = \sqrt{ {x}^{2} + {y}^{2} }$

The given complex number is:

$z = 4 - 10i$

$r = \sqrt{ {4}^{2} + {( - 10)}^{2} }$

$r = \sqrt{16 + 100}$

$r = \sqrt{116} = 2 \sqrt{29}$

And

$\theta= \tan^{ - 1}(\frac{ y}{x} )$

$\theta= \tan^{ - 1}(\frac{ - 10}{4} )$

$\theta= 292 \degree$

Hence the polar form is :

$r = 2 \sqrt{29} ( \cos(292 \degree) + \sin(292 \degree))$

6 0

3 years ago

What is the interquartile range of the data set?

AveGali [126]

There is no data provided but if your asking what an interquartile range is ?? It’s a measure of variability based on dividing a data set into quartile a

6 0

2 years ago

What is the cross-sectional area of a wire if its outside diameter is 0.0625 inch?

Leno4ka [110]

Given that the diameter: d= 0.0625 inch.

So, radius of the wire : r = $\frac{0.0625}{2}$ = 0.03125 inch

Now the formula to find the cross-sectional area of wire ( circle) is:

A = πr²

= 3.14 * (0.03125)² Since, π = 3.14 and r = 0.03125

=3.14 * 0.000976563

= 0.003066406

= 0.00307 (Rounded to 5 decimal places).

Hence, cross-sectional area of a wire is 0.00307 square inches.

Hope this helps you!

5 0

2 years ago

Read 2 more answers