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3 years ago

How do I solve this? Please explain step by step,thankyou!

Mathematics

2 answers:

umka2103 [35]3 years ago

4 0

Answer:

Hey there!

Angle x would be 62 degrees because angles in a triangle add to 180 degrees.

Let me know if this helps :)

Brrunno [24]3 years ago

3 0

Answer:

x = 62 degrees

Step-by-step explanation:

Total degrees of a triangle = 180

=> 68.5 + 49.5 + x = 180

=> 118 + x = 180

=> 118 - 118 + x = 180 - 118

=> x = 62

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Solve the given inequality. Describe the solution set using the set-builder or interval notation. Then, graph the solution set o

Korolek [52]

Answer:

Step-by-step explanation:

10(10m+6)<=12

100m+60<=12 Distributive Property

100m <=12-60

100m <=-48

m <=-48/100

m <=-.48

This says values for m that are less than or equal to -.48

-.48 is between -1 and 0 so the answer is B

6 0

3 years ago

Read 2 more answers

Pleaseeeeeeeeeeeeee helppppppppppp

sergeinik [125]

Answer:

Step-by-step explanation:

8) (5x + 23) + (17x - 41) = 180

22x = 198

x = 9

arc JK 5(9) + 23 = 68°

arc MJ 17(9) - 41 = 112°

arc LMK 360 - 112 = 248

9) 8x + (21x - 12) + (10x + 9) + 90 = 360

39x = 273

x = 7

arc WX 21(7) - 12 = 135°

arc YW 90 + 8(7) = 146°

arc YX 10(7) + 9 = 79°

arc VXW 360 - 8(7) = 304°

6 0

3 years ago

What is the balance as a result of having a credit of $84 and a debit of $29

Aleks [24]

The answer is $113 because you add the money

6 0

3 years ago

Please see attachment

Dafna11 [192]

Answer:

a) The value of absolute minimum value = - 0.3536

b) which is attained at $x = \frac{1}{\sqrt{2} }$

Step-by-step explanation:

Step(i):-

Given function

$f(x) = \frac{-x}{2x^{2} +1}$ ...(i)

Differentiating equation (i) with respective to 'x'

$f^{l} = \frac{2x^{2} +1(-1) - (-x) (4x)}{(2x^{2}+1)^{2} }$ ...(ii)

$f^{l}(x) = \frac{2x^{2}-1}{(2x^{2}+1)^{2} }$

Equating Zero

$f^{l}(x) = \frac{2x^{2}-1}{(2x^{2}+1)^{2} } = 0$

$\frac{2x^{2}-1}{(2x^{2}+1)^{2} } = 0$

$2 x^{2}-1 = 0$

$2 x^{2} = 1$

$x^{2} = \frac{1}{2}$

$x = \frac{-1}{\sqrt{2} } , x = \frac{1}{\sqrt{2} }$

Step(ii):-

Again Differentiating equation (ii) with respective to 'x'

$f^{ll}(x) = \frac{(2x^{2} +1)^{2} (4x) - 2(2x^{2} +1) (4x)(2x^{2}-1) }{(2x^{2}+1)^{4} }$

put

$x = \frac{1}{\sqrt{2} }$

$f^{ll} (x) > 0$

The absolute minimum value at $x = \frac{1}{\sqrt{2} }$

Step(iii):-

The value of absolute minimum value

$f(x) = \frac{-x}{2x^{2} +1}$

$f(\frac{1}{\sqrt{2} } ) = \frac{-\frac{1}{\sqrt{2} } }{2(\frac{1}{\sqrt{2} } )^{2} +1}$

on calculation we get

The value of absolute minimum value = - 0.3536

Final answer:-

a) The value of absolute minimum value = - 0.3536

b) which is attained at $x = \frac{1}{\sqrt{2} }$

3 0

3 years ago

The point (1,−1) satisfies the inequality 40x−22y≤50.

Natalka [10]

Không thảo mãn vì

44.1-22.(-1)=66

7 0

3 years ago